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Ahat [919]
3 years ago
12

Question 2

Mathematics
1 answer:
choli [55]3 years ago
8 0
%6 of the sixth graders are left handed
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Write a sentence to answer each question:<br><br> How much warmer is 82 than 40?
Lostsunrise [7]

Answer:

82 is 42 degrees warmer than 40

Step-by-step explanation:

if you subtract 40 from 82, you get 42 meaning that the answer will be 42 degrees more than 40

8 0
2 years ago
An airplane leaves New York to fly to Los Angeles. It travels 3,850 km in 5.5 hours. What is the velocity of the airplane?
Ilya [14]

Answer:

C. 700 km/hour

Step-by-step explanation:

7 0
2 years ago
Find the future value of an annuity due of $7,000 paid at the beginning of each 6-month period for 8 years if the interest rate
Oliga [24]

Answer: Im not sure but i think its 120,960

Step-by-step explanation: i know that there is 2 of the 6-month periods in a year and multiplied that by 8 and got 16. Then i did 7000x.08=560 and then i added that to 7000 and got 7560. FInally i multiplied that by 16 and got 120,960.

4 0
2 years ago
In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until
Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There are 12 bulbs, hence N = 12.
  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

  • Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
  • The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0
2 years ago
Bruh can someone answer this I’ll give brainliest
3241004551 [841]
It’s a ! you add both of the numbers to get your missing perimeter.
I’m very sorry if it’s wrong but this is what I believe! stay safe
4 0
2 years ago
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