1) area of a cicular pool
area of a circle=πr^2 d=2.5 then r=2.5/2
A=3.14 *(2.5/2)^2
A=4.906m^2 A=4.9m^2

2) arae of a coin
<span>(if i read it right d=15mm?)
</span>A=πr^2 d=15 then r=15/2
A=3.14*(15/2)^2 =176.6mm^2

Rest all are same problems u try to solve it

4 0

4 years ago

I need help.. A diameter of a circle has endpoints p(-10, -2) and q(4, 6)

Phoenix [80]

A: The center is the mid point of the diameter. So, the center of the circle will be the midpoint of points P and Q. The coordinates of the midpoint are the averaged coordinates of the endpoints.

So, the x-cooardinate of the center is the average of the x-coordinates of P and Q:

$C_x = \dfrac{P_x+Q_x}{2}=\dfrac{-10+4}{2}=\dfrac{-6}{2}=-3$

Try to do the same thing with the y coordinates, and you'll get the y-coordinate $C_y$ . This first part will be over, because the circle will be point

$C=(C_x,C_y)$

B: The radius is exactly half the diameter. So, we find the length of the diameter, and we divide it by 2. To find the length of the diameter, we use the standard formula for the distance between two points:

$d=\sqrt{(P_x-Q_x)^2+(P_y-Q_y)^2}=\sqrt{(-10-4)^2+(-2-6)^2}=\sqrt{260}=2\sqrt{65}$

Divide this length by 2 and you'll get the radius.

C: At this point, we have both the radius and the coordinates of the center. The equation of the circle depends on these two parameters, and it is

$(x-C_x)^2+(y-C_y)^2=r^2$

Substitute $C_x$ and $C_y$ with the coordinates of the center (found in point A.) and $r$ with the radius (found in point B.) and you'll have the equation of the circle.

6 0

3 years ago

All help is much appreciated please and thank you

Klio2033 [76]

Once again similar traingles.

With same ratioes as before.

RS/RT = RV/RU=SV/TU = 1/2

$\frac{w - 41}{w} = \frac{1}{2} \\ 2w - 82 = w \\ w = 81 \: units$

5 0

3 years ago

What are solutions for the equation y=8x-5

Semmy [17]

Answer:

Multiple

Step-by-step explanation:

You put the equation in slope intercept form, therefore, the solutions are the entire line!

Every point on the line can be considered a solution.

4 0

3 years ago