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Salsk061 [2.6K]
3 years ago
6

Round 86,124 to the nearest ten thousand

Mathematics
1 answer:
kirill [66]3 years ago
7 0
When rounding any number anything greater than 5 you go up and anything less than 5 you round down.
nearest ones 86120 ( 4 is lower than 5 you go down)
nearest tens 86100 ( 2 islower than 5 you go down)
nearest hundreds 86000( 1 is lower than 5 you go down)
nearest thousands 87000 ( 6 higher than 5 you go up)
nearest ten thousands 90000 ( 8 is higher than 5 you go up)
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What is the vertex of the graph of y = x2 + 4x?<br> (–2, –12)<br> (–2, –8)<br> (–2, –6)<br> (–2, –4)
SCORPION-xisa [38]

Answer: The vertex of the parabola (quadratic function) is (-2,-4)

Fourth option: (-2,-4)


Solution:

y=x^2+4x

y=ax^2+bx+c; a=1, b=4, c=0

Vertex: V=(h,k)

h=-b/(2a)

h=-4/(2(1))

h=-4/2

h=-2

y=x^2+4x

k=y=h^2+4h

k=(-2)^2+4(-2)

k=4-8

k=-4

Vertex: V=(h,k)

Vertex: V=( -2, -4)



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4 years ago
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The two polygons are similar. Find the measure of angle U.<br> 120°<br><br> 185°
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It’s 80 for sure Ik this one
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Lyte wishes to study speed of Reaction Time to press a button in response to the onset of a lamp. The independent variable (V) i
Vaselesa [24]

Complete question:

Dr. Lyte wishes to study speed of Reaction Time to press a button in response to the onset of a lamp. The independent variable (V) is the color of the light produced by the lamp (red, orange, yellow, green, or blue) Since only 10 participants are available, she elects to administer the IV within-subjects with all 10 participants being exposed to all five levels of the color variable. The order of the color of the light presentation is to be counterbalanced. Using concepts from the textbook, why would Dr. Lyte need to use counterbalancing in this scenario?

Answer:

Here,

Independent variable (IV) is: the color of the light produced by the lamp (red, orange, yellow, green, or blue)

We are also told only 10 participants are available.

All 10 participants are being exposed to all five levels of the color variable in the same order.

Counterbalancing is said to be a technique used when establishing task order. It helps prevent introduction if cofounding variables.

Dr. Lyte will need to use counterbalancing technique in this scenario because some of the participants may be unable to understand difference in similar colours. Example some participants may not be able to differentiate between orange and red when the red colour comes after orange.

But using counterbalancing technique, Dr. Lyte can avoid such an error.

6 0
4 years ago
P: x – 5 =10 q: 4x + 1 = 61 Which is the inverse of p → q?
Lesechka [4]
The inverse is b.  If 4x+1 .NE. 61, then x-5 .NE.10
3 0
3 years ago
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On a coordinate plane, 3 triangles are shown. Triangle B C D has points (1, 4), (1, 2), (5, 3). Triangle B prime C prime D prime
Tresset [83]

The rule which describe the composition of transformations that

maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis composition translation of 6 units x,

negative 5 units y ⇒ last answer

Step-by-step explanation:

Let us revise the reflection across the y-axis , horizontal translation

and vertical translation

1. If point (x , y) is reflected across the y-axis, then its image is (-x , y)

2. If point (x , y) is translated h units to the right, then its image is

   (x + h , y), if translated h units to the left, then its image is (x - h , y)

3. If point (x , y) is translated k units up, then its image is (x , y + k),

   if translated k units down, then its image is (x , y - k)

∵ The vertices of triangle BCD are (1 , 4) , (1 , 2) , (5 , 3)

∵ The vertices of triangle B'C'D' are (-1 , 4) , (-1 , 2) , (-5 , 3)

∵ The x-coordinates of the vertices of Δ B'C'D' have the same

   magnitude of x-coordinates of Δ BCD and opposite signs

∴ Δ B'C'D' is the image of Δ ABC after reflection across the y-axis

∵ The vertices of triangle B'C'D' are (-1 , 4) , (-1 , 2) , (-5 , 3)

∵ The vertices of triangle B''C''D'' are (5 , -1) , (5 , -3) , (1 , -2)

∵ The image of -1 is 5 and the image of -5 is 1

∴ The x-coordinates of the vertices of triangle B'C'D' are added by 6

∵ The image of 4 is -1 , image of 2 is -3 and the image of 3 is -2

∴ The y-coordinates of the vertices of triangle B'C'D' are subtracted

   by 5

∴ Δ B"C"D" is the image of Δ B'C'D' by translate 6 units to the right

  and 5 units down ⇒ (x + 6 , y - 5)

The rule which describe the composition of transformations that

maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis composition translation of 6 units x,

negative 5 units y

Learn more:

You can learn more about reflection in brainly.com/question/11203617

#LearnwithBrainly

3 0
3 years ago
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