Answer:
<em>2000 m</em>
<em></em>
Explanation:
since the boat is 1000 m from the river bank, the beam must be focused at this point. This indicates that the focal length is 1000 m
for a spherical mirror, the focal length is given by
f = R/2
where R is the radius of curvature
1000 = R/2
R = 2000 m
R = 2000 m
this means that <em>the radius of curvature must be 2000 m</em>
Answer:
Frequency,
Explanation:
Visible red light has a wavelength of 680 nanometers (6.8 x 10⁻⁷ m). The speed of light is 3.0 x 10 ⁸ m / s. What is the frequency of visible red light?
It is given that,
Wavelength of a visible red light is,
Speed of light is,
We need to find the frequency of visible red light. It can be calculated using below relation.
So, the frequency of visible red light is .
As a substance is changing from a liquid to a gas, the distance between its molecules increases, and the temperature of the system remains the same.
Option A
<u>Explanation:</u>
The external energy required to change from one state to another is mostly considered as temperature. So on increase in temperature, the solid changes to liquid and the liquid changes to gases. But the temperature remains constant in the system after changing the phase.
This is because when the temperature is increased on a liquid system, the rise in temperature is utilized for breaking the bonds and thus the molecules will be distanced from each other. If we consider liquid - gas phase transition, the gas molecules are farther distanced compared to liquid molecules.
So the rise in temperature is utilized for breaking the bonds and also to provide the kinetic energy to the gas molecules as they are tend to move more freely compared to liquid. Thus, the distance between the molecules increases, and the temperature of the system remains the same on changing from liquid to gas.
Answer:
Time needed is 2.5 seconds. The distance covered is 31.3 m
Explanation:
Answer:
Explanation:
Given:
- mass of the one ion,
- mass of another ion,
- velocity of projection into the magnetic field,
- charge on each ion,
- magnetic field,
We have, force on a charged particle due to the perpendicular magnetic field:
............................(1)
Force on mass moving in a circular trajectory
...............................(2)
where "r" is the radius of trajectory.
from eq. (1) & (2)
putting the values for the condition 1:
putting the values for the condition 2:
∵The charges have covered a semicircular path from the point of entrance,
∴ their difference in the radius will give their distance from each other.