The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>
From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3 ![\sqrt[8]{15}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B15%7D)
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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Answer:
Step-by-step explanation:
Using I = PRT/100
where P = The principal amount invested = $5500
R = Rate of Interest =5%
T = Time (in years)
I = Interest = $7,739.05 - $5500 = $2239.05
Substituting the above values in the formula
I = PRT/100 becomes
2239.05 = 7,739.05 * 5 * t / 100 -------- Multiply 100 to both sides
2239.05 * 100 = 100 * 7739.05 * 5 * t / 100
223905 = 7739.05 * 5 * t
223905 = 38695.25t
Divide both sides by 38695.25t
223905/38695.25 = t
5.786369 = t
T = 5.79 (approximated)
Katelyn because there are 3 feet in 1 yard therefore, Dave is 2616 feet away from school.
