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jok3333 [9.3K]
3 years ago
9

JT EspanolYou roll one die. What is the probability that you roll a 6?​

Mathematics
2 answers:
Alinara [238K]3 years ago
6 0

Answer:

1/6

Step-by-step explanation:

A die has 6 sides, due to it being a cube, as a result there are 6 possible outcomes when rolling a dice, therefore, if you role it once there is a 1/6 chance you will roll a 6.

DENIUS [597]3 years ago
3 0
The probability of rolling a six if you roll one die is 1/6
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Brainliest!, write an algebraic expression to represent the verbal expression
Len [333]

Answer:

  (n/24)^3

Step-by-step explanation:

If "n" represents "a number," then "the quotient of a number and 24" means ...

  (n/24)

The cube of that is ...

  (n/24)^3

4 0
3 years ago
Read 2 more answers
The model shows 1/2.
cestrela7 [59]

Answer:

the answer is B

Step-by-step explanation:

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3 years ago
An elevator has a placard stating that the maximum capacity is 1600 lb�10 passengers.​ So, 10 adult male passengers can have a m
Bezzdna [24]

Answer:

1. 0.7421 = 74.21% probability the elevator is overloaded.

2. D.​No, there is a good chance that 10 randomly selected people will exceed the elevator capacity.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume that weights of males are normally distributed with a mean of 166 lb and a standard deviation of 29 lb​.

This means that \mu = 166, \sigma = 29

Sample of 10.

This means that n = 10, s = \frac{29}{\sqrt{10}}

1.The probability the elevator is overloaded is?

Probability that the sample mean is above 160 pounds, which is 1 subtracted by the p-value of Z when X = 160. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 166}{\frac{29}{\sqrt{10}}}

Z = -0.65

Z = -0.65 has a p-value of 0.2579.

1 - 0.2579 = 0.7421

0.7421 = 74.21% probability the elevator is overloaded.

2. Does this elevator appear to be​ safe?

High probability of the elevator being overloaded, so not safe. Correct answer is given by option D.

7 0
3 years ago
New York City is the most expensive city in the United States for lodging. The mean hotel room rate is $204 per night. Assume th
vovangra [49]

Answer:

z=0.842

And if we solve for a we got

a=204 +0.842*55=250.31

So the value of height that separates the bottom 80% of data from the top 20% is 250.31.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the room hotel rate of a population, and for this case we know the distribution for X is given by:

X \sim N(204,55)  

Where \mu=204 and \sigma=55

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.20   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.80 of the area on the left and 0.20 of the area on the right it's z=0.842. On this case P(Z<0.842)=0.8 and P(z>0.842)=0.2

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.842

And if we solve for a we got

a=204 +0.842*55=250.31

So the value of height that separates the bottom 80% of data from the top 20% is 250.31.  

4 0
3 years ago
0.4.07<br> Jim is 7 ft 10 in tall. Jane is 23.5 in tall. How many times taller than Jane is Jim?
faust18 [17]

Answer:Jane is 16.5in. taller than Jim.

Step-by-step explanation:

8 0
4 years ago
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