Answer:
5 cm
Step-by-step explanation:
We khow that the altitude of this triangle is 1cm shorter than the base
- Let H be our altitude and B our base and A the area of the triangle
- A= (B*H)/2 ⇒ 15=(B*H)/2
- H is 1cm shorter than B ⇒ B=H+1
- H*(H+1)/2=15 ⇒ H*(H+1)=30⇒ H²+H=30⇒H²+H-30+0
that's a quadratic equation . Let's calculate the dicriminant .
Let Δ be the dicriminant
- a=1
- b=1
- c= -30
- Δ=b²-4*a*c = 1²-4*1*(-30)=1+4*30=121≥0
- Δ≥0⇔ that we have two solutions x and y
- x= (-1-
)/2= (-1-11)/2= -6 - y= (-1+
)/2= 10/2 = 5
We have a negative value and a positive one
The altitude is a distance so it can't be negative
H= 5cm
Answer:
Increases, same, increases, decreases
Step-by-step explanation:
I mean just look at the graph
V=hpir^2
tricky, they didn't give us radius
they just gave circiufmerece
c=2pir
25.12=2pir
divide by 2 both sides
12.56=pir
divide by 3.14 both sides
4=r
subsitutet
v=hpir^2
v=66pi4^2
v=66pi16
v=1056pi
v=3315.84 cubic inches
we are given
quadratic equation as

now, we can find b and c from

we can see that coefficient of x^2 is 1
so, we will have to make coefficient x^2 as 1
so, we divide both sides by 3



now, we can simplify it

now, we can compare it with

we get


so, we get order pair as
..............Answer