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Masteriza [31]
3 years ago
7

Wren’s first display box is 6 inches long, 9 inches wide, and 4 inches high. What is the volume of the display box? Explain your

work using a diagram.

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
7 0

Answer:

\text{Volume of display box}=216\text{ in}^3    

Step-by-step explanation:

We have been given that Wren’s first display box is 6 inches long, 9 inches wide, and 4 inches high. We are asked to find the volume of display box.

We know that the box is in form of cuboid, so its volume would be length times width times height.

\text{Volume of display box}=6\text{ in}\times 9\text{ in}\times 4\text{ in}

\text{Volume of display box}=216\text{ in}^3

Therefore, the volume of the display box is 216 cubic inches.

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A florist can make a grand arrangement in 18 minutes or a simple arrangement in 10 minutes. The florist makes at least twice as
Colt1911 [192]

Answer:

See explanation

Step-by-step explanation:

Let x be the number of simple arrangements and y be the number of grand arrangements.

1. The florist makes at least twice as many of the simple arrangements as the grand arrangements, so

x\ge 2y

2. A florist can make a grand arrangement in 18 minutes =\dfrac{3}{10} hour, then he can make y arrangements in \dfrac{3}{10}y hours.

A florist can make  a simple arrangement in 10 minutes =\dfrac{1}{6} hour, so he can make x arrangements in \dfrac{1}{6}x hours.

The florist can work only 40 hours per week, then

\dfrac{3}{10}y+\dfrac{1}{6}x\le 40

3. The profit on the simple arrangement is $10, then the profit on x simple arrangements is $10x.

The profit on the grand arrangement is $25, then the profit on y grand arrangements is $25y.

Total profit: $(10x+25y)

Plot first two inequalities and find the point where the profit is maximum. This point is point of intersection of lines x=2y and \dfrac{3}{10}y+\dfrac{1}{6}x=40

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\$(10\cdot 126+25\cdot 63)=\$2,835

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