There is no solution. Here is the explanation with both of the methods :)
The value of the function 1) f -g = 2x² - 3x + 6 and 2) f(g(2)) is 3.
Here the two functions are given, f(x) and g(x).
f(x) = 2x² + 1
g(x) = 3x - 5
We have to find f-g and f(g(2)).
1) f- g
f(x) - g(x)
(2x² + 1) - ( 3x - 5)
2x² + 1 - 3x + 5
2x² - 3x + 6
2) f(g(2))
f(g(x)) = 2(3x-5)² + 1
= 2( 9x² - 30x + 25) + 1
= 18x² - 60x + 50 + 1
= 18x² - 60x + 51
f(g(2)) = 18(2)² - 60(2) + 51
=18× 4 - 120 + 51
= 72 - 120 + 51
= 123 - 120
= 3
Therefore the value of f-g is 2x²- 3x + 6 and the value of f(g(2)) is 3.
To know more about the function refer to the link given below:
brainly.com/question/11624077
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Solutions are 3 and - 5.
Step-by-step explanation:
Step 1:
Given equation is 3x² + 6x = 45. Factorize the equation to get the solutions.
⇒ 3x² + 6x - 45 = 0
⇒ x² + 2x - 15 = 0
⇒ x² + 5x - 3x - 15 = 0 (Product and Sum Method where product of coefficients = - 15 and sum = 2)
⇒ x (x + 5) - 3(x + 5) = 0
⇒ (x - 3)(x + 5) = 0
⇒ x = 3, - 5
Lets make it an improper fraction
5/3
we do not know how many chains so we'll put the (x)
therefore
5/3x=9.00
x= 5.4