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3 years ago

Need Help Please!!!!,

Mathematics

1 answer:

OverLord2011 [107]3 years ago

5 0

$f(x)=\dfrac{7x}{x-3}\\\\The\ domain:\\x-3\neq0\ \ \ \ |+3\\\\x\neq3$

Answer: All real numbers except 3

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Collect like terms/equations

Vlad [161]

1. -3x and -6x
2. 21 and -13
3. 21 and -13
4. -10b and 6b, 15 and -5
5. -20 and 30, 4c and -2c

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3 years ago

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Which of the following are quadratic equations

Igoryamba

Answer:

<h2>HOPE U UNDERSTOOD</h2>

★THANKS★

ANY DOUBTS? COMMENT PLEASE

6 0

3 years ago

Can you help me !!!!!

kari74 [83]

Answer:

Step-by-step explanation:

Okay, so hopefully my crude diagram helps you visualize the problem. When in doubt, always draw a picture.

All I did was graph the points and formed a line.

Slope: It's going to be 0 because it doesn't change at all (no different y values)

(y2-y1)/(x2-x1) = (6-6) / (4-2) = 0/2 = 0

Y intercept is where the line crosses the y axis- this is also where x=0 (find it in your chart!)

Equation is y= 6; I don't know how to explain this, but trust me, it's right

8 0

3 years ago

Consider the given solids with the dimensions shown. Which solids are similar? three rectangular prisms. Figure 1 is 8 meters by

professor190 [17]

Answer: figures 1 and 3 i think

Step-by-step explanation:

16/9=64/36 18/12 doesnt

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3 years ago

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A teacher was interested in finding out whether a special study program would increase the scores of students on a national exam

bija089 [108]

Answer:

Check the explanation

Step-by-step explanation:

Going by the first attached image below we reject H_o against H_1 if obs. $T > t_{\alpha /2;n-1}$

here obs.T=1.879

$\therefore obs.T \ngtr 2.447=t_{0.025;6}$

we accept $H_o:\mu _{1}=\mu_{2}$ at 5% level of significance.

i.e there is no sufficient evidence to indicate that the special study program is more effective at 5% level of significance.

this problem is simillar to the previous one except the alternative hypothesis.

Let X_i's denote the bonuses given by female managers and Y_i's denote the bonuses given by male managers.

we assume that $X_i \sim N(\mu _{1},\sigma _{1}^{2}) Y_i \sim N(\mu _{2},\sigma _{2}^{2})$ independently

We want to test $H_0:\mu_{1}=\mu_{2} vs H_1:\mu_{1}\neq \mu_{2}$

define $D_i=X_i-Y_i , i=1(1)8$

now $D_i\sim N(\mu _{1}-\mu _{2}=\mu _{D},\sigma _{1}^{2}+\sigma _{2}^{2}=\sigma _{D}^{2}) , i=1(1)8$

the hypothesis becomes

$H_0:\mu_{D}=0 vs H_1:\mu_{D}\neq 0$

in the third attached image, we use the same test statistic as before

i.e at 5% level of significance there is not enough evidence to indicate a difference in average bonuses .

3 0

3 years ago