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ella [17]
3 years ago
12

Need Help Please!!!!,

Mathematics
1 answer:
OverLord2011 [107]3 years ago
5 0

f(x)=\dfrac{7x}{x-3}\\\\The\ domain:\\x-3\neq0\ \ \ \ |+3\\\\x\neq3

Answer: All real numbers except 3

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A cylindrical swimming pool has a diameter of 16 feet and a height of 4 feet. About how many gallons of water can the pool conta
nikklg [1K]

HOPE THIS HELPS YOU!!!

8 0
3 years ago
Identify the sine function with the given attributes.
Thepotemich [5.8K]

Answer:

<em>Last option </em>

f(t)=sin(\pi(t -3)) + 4

Step-by-step explanation:

The general sine function has the following form  

y = Asin(bt-\phi) + k

Where A is the amplitude: half the vertical distance between the highest peak and the lowest peak of the wave.  

\frac{2\pi}{b} is the period: time it takes the wave to complete a cycle.

k is the vertical displacement.

\phi phase shift

We know that:

amplitude: 1; period: 2; phase shift: 3; vertical shift: 4

Thus:

A =1

\frac{2\pi}{b}=2

b=\pi

\phi=3

k=4

Then the function is:

f(t)=sin(\pi(t -3)) + 4

The answer is last option

4 0
3 years ago
I have these factoring questions I need help with.
snow_lady [41]

f(x)=4x^2+4x-3

1. Determine y-intercept.

<em>The y-intercept is (0,-3). Substitute x = 0 in the equation as we get f(x) = -3 as the y-intercept.</em>

2. Determine the zeros.

<em>Factor the polynomials first. </em>(2x-1)(2x+3) <em>This is the factored form. The zeros are the roots of equation. Therefore, the zeros are 1/2 and -3/2</em>

3. Determine the Axis of Symmetry

<em>We can solve this by using the formula of </em>x=-\frac{b}{2a}  <em>However, I'll be solving the Axis of Symmetry with Calculus instead.</em>

<em />f'(x)=2(4x^{2-1})+1(4x^{1-1})-0\\f'(x)=8x+4<em />

<em>Then let f'(x) = 0 to find the Axis of Symmetry.</em>

<em />8x+4=0\\8x=-4\\x=-\frac{4}{8}\\x=-\frac{1}{2}<em />

<em>Therefore, the Axis of Symmetry is -1/2</em>

4. Determine the vertex.

<em>Substitute the value of Axis of Symmetry in f(x).</em>

<em />f(x)=4(-\frac{1}{2})^2+4(-\frac{1}{2})-3\\f(x)=4(\frac{1}{4})-2-3\\f(x)=1-2-3\\f(x)=-4<em />

<em>Therefore the vertex is at (-1/2, -4)</em>

5. Does the vertex representing max-pont or min-point?

<em>The vertex represents the minimum point. The graph is upward, meaning the minimum point is the point that gives the LOWEST Y-VALUE. </em>

7. Graph f(x)

<em>Unfortunately I won't be able to graph. But I can tell you to graph a parabola that has the most curve at the vertex and intercepts y-axis at (0,-3).</em>

<em>--------------------------- </em>End of Part 1 --------------------------------

2. Write the general form of Quadratic Function in standard form.

y=ax^2+bx+c

<em>The graph can be easily determined about the y-intercept and being an upward or downward parabola along with how narrow or wide the parabola is. </em>

<em>For example, c value is the y-intercept as defined. When a > 0, the parabola is upward and when a < 0, the parabola is downward. The more value of | a | is, the more narrow it will be and the less value of | a | it is, the wider it will be.</em>

3. Write in Factored Form

y=(x+a)(x+b)\\y=(x-a)(x-b)\\y=(x+a)(x-b)\\y=(x-a)(x+b)

<em>These are factored forms with different types of operators.</em>

<em>The equation can be easily determined about the roots of equation. For example, if the function is in f(x) = (x+2)(x-1) Then the roots would be x = -2 and 1 as the graph will intercept x-axis at (-2,0) and (1,0)</em>

4. Write in Vertex Form.

y=a(x-h)^2+k

<em>The equation can be easily determined for the vertex, axis of symmetry and the same narrow/wide/upward/downward parabola again.</em>

<em>The vertex is at (h,k) and the axis of symmetry is at x = h.</em>

<em>For example, </em>y=(x-2)^2+3<em />

<em>The vertex would be at (2,3) and the axis of symmetry is x = 2.</em>

3 0
3 years ago
A car travels 15 1/10 miles in 1/3 of an hour. What is the average speed, in
jasenka [17]

Step-by-step explanation:

Miles = 15 1/10

Miles = 151/10 miles

Hour = 1/3 hour

Av = 151/10 miles / 1/3 hour

Av = 151/10 × 3 / 1/3 × 3

Av = 453/10 miles / hour

Av = 45,3 mil / h

4 0
3 years ago
Read 2 more answers
A mirror is in the shape of an isosceles right triangle and has a hypotenuse length of seven times the square root of two. What
frez [133]

The length of one of the legs  of an isosceles right triangle and has a hypotenuse length of seven times the square root of two is 7 units.

<h3>What is an Isosceles triangle?</h3>

Isosceles triangles are triangles that has two of it sides equal to each other. The base angles of an isosceles triangle are equal.

The  isosceles triangle is also a right angle triangle. The hypotenuse is the longest side of a right angle triangle.

Therefore,

hypotenuse = 7(√2)

let the length of the other legs = x

Therefore, using Pythagoras theorem

c² = a² + b²

(7(√2))² = x² + x²

49 × 2 = 2x²

98 = 2x²

x² = 98 / 2

x = √49

x = 7 units

learn more on isosceles triangle here: brainly.com/question/10412877

4 0
2 years ago
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