The number of terms in the given arithmetic sequence is n = 10. Using the given first, last term, and the common difference of the arithmetic sequence, the required value is calculated.
<h3>What is the nth term of an arithmetic sequence?</h3>
The general form of the nth term of an arithmetic sequence is
an = a1 + (n - 1)d
Where,
a1 - first term
n - number of terms in the sequence
d - the common difference
<h3>Calculation:</h3>
The given sequence is an arithmetic sequence.
First term a1 = = 3/2
Last term an = = 5/2
Common difference d = 1/9
From the general formula,
an = a1 + (n - 1)d
On substituting,
5/2 = 3/2 + (n - 1)1/9
⇒ (n - 1)1/9 = 5/2 - 3/2
⇒ (n - 1)1/9 = 1
⇒ n - 1 = 9
⇒ n = 9 + 1
∴ n = 10
Thus, there are 10 terms in the given arithmetic sequence.
learn more about the arithmetic sequence here:
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Disclaimer: The given question in the portal is incorrect. Here is the correct question.
Question: If the first and the last term of an arithmetic progression with a common difference are , and 1/9 respectively, how many terms has the sequence?
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Answer:
the two points are (-3,-3
Step-by-step explanation:
You must first check if the line is a straight line two the you check the intersection of the two points and the write it
Answer:
19/30
Step-by-step explanation:
We need to get a common denominator of 30
4/5 *6/6 = 24/30
1/6 *5/5 = 5/30
4/5 - 1/6
24/30 - 5/30
19/30
The correct answer 19.42
circumference of a circle= 2(3.14)r
2(3.14)(3)=18.84 but its half a circle so divide by 2 18.84/2=9.42
9.42+6+4=19.42