Set up an algebraic equation: b=cost of ball
1.10=1+b+b
1.10=1+2b
subtract 1 from both sides
.10=2b
divide by 2 on both sides
ball=5 cents
I think C would equal 15, because 14 + 14 = 28; 15 + 15 = 30 which is greater than 28.
Answer:
X = 13
1. Add 8 to both sides of the equation
5
Assume that,
adult = x
child = y
x+2y = 35 (1st equation)
2x+3y = 60 (2nd equation)
x = 35-2y (3rd equation)
Substitute 3 into 2 :
2(35-2y) + 3y =60
70-4y +3y = 60
y = 10
x+2y = 35
x+2(10) =35
x +20 =35
x = 15
One adult = $15
