When 23 is subtracted from 5 times a certain number the result is 87
1 answer:
You might be interested in
Answer:
<h2>AC = 36.01</h2>Step-by-step explanation:
Given ΔABC and ΔADB, since both triangles are right angled triangles then the following are true.
From ΔADB, AB² = AD²+BD²
Given AB = 24 and AD = 16
BD² = AB² - AD²
BD² = 24²-16²
BD² = 576-256
BD² = 320
BD =
BD = 17.9
from ΔABC, AC² = AB²+BC²
SInce AC = AD+DC and BC² = BD² + DC² (from ΔBDC )we will have;
(AD+DC)² = AB²+ (BD² + DC²)
Given AD = 16, AB = 24 and BD = 17.9, on substituting
(16+DC)² = 24²+17.9²+ DC²
256+32DC+DC² = 24²+17.9²+ DC²
256+32DC = 24²+17.9²
32DC = 24²+17.9² - 256
32DC = 640.41
DC =
DC = 20.01
Remember that AC = AD+DC
AC = 16+20.01
AC = 36.01
The sum of the balances of these accounts at the end of 5 years is given by: Option B: $53,901.59 (approx)
<h3>How to calculate compound interest's amount?</h3>If the initial amount (also called as principal amount) is P, and the interest rate is R% per unit time, and it is left for T unit of time for that compound interest, then the interest amount earned is given by:
The final amount becomes:
If the initial amount (also called as principal amount) is P, and the interest rate is R% annually, and it is left for T years for that simple interest, then the interest amount earned is given by:
For the considered case, we're given that:
- Initial amount in both accounts deposited = $24,000 = P
- Type of interest: Compound interest in first account and simple interest in second account
- Unit of time: Annually
- Rate of interest = 2.4% annually = R
- Total unit of time for which amount is to be calculated: 5 years = T
In first account, the final amount at the end of 5 years is evaluated as:
In second account, the final amount at the end of 5 years is evaluated as:
Total amount after 5 years in these accounts = (in dollars)
Thus, the sum of the balances of these accounts at the end of 5 years is given by: Option B: $53,901.59 (approx)
Learn more about compound interest here: