1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yanka [14]
3 years ago
12

When 23 is subtracted from 5 times a certain number the result is 87

Mathematics
1 answer:
allsm [11]3 years ago
8 0
5x-23=87
add 23 to both sides
5x=110
divide both sides by 5
x=22

To check your answer...
5(22)-23=87
110-23=87
87=87
You might be interested in
Correlation coefficients fall in a scale from -1.0 to 1.0 and show how ________ the points are on the scatter plot around a ____
Shkiper50 [21]
Did they give multiple Choice
7 0
3 years ago
VI. PRACTICE TASKS
dimulka [17.4K]

Step-by-step explanation:

1 _ 1.215

2_ 4.0608

3_1.5225

4_0.2875

5_3.6064

8 0
2 years ago
A gardener already has four and one over 2 ft of fencing in his garage. He wants to fence in a square garden for his flowers. Th
NikAS [45]
<h2>Answer:</h2>

6\frac{1}{2}<u>, "six and one over two ft".</u>

<h2>Step-by-step explanation:</h2>

Let's considerate the fact that the garden has a <u>square shape</u>.

<h3>1. Finding values of interest.</h3>

Amount of fence that the gardener already has: 4\frac{1}{2} ft.

Length of one side: 2\frac{3}{4} ft.

If one side measures 2\frac{3}{4} ft, and the square garden has 4 sides of equal length, because it's a square, then we must multiply the measure of one side by 4 to find the total length of fence needed:

4*(2\frac{3}{4})=\\ \\4*(2+\frac{3}{4})=\\ \\(4*2)+(4*\frac{3}{4})=\\ \\8+(\frac{12}{4} )=\\ \\8+3=\\ \\11

<h3>2. How much more does he need?</h3>

The gardener already has  4\frac{1}{2} , which equals 4 + \frac{1}{2}. Hence, the difference between the amount needed and the amount that the gardeneralready has will give us the remaining amount required. Let's do that:

11-(4+\frac{1}{2} )=\\ \\11-(\frac{8}{2} +\frac{1}{2} )=\\ \\11-\frac{9}{2}= \\ \\\frac{22}{2} -\frac{9}{2}=\\\\ \frac{13}{2}

<h3>3. Express your result.</h3>

\frac{13}{2} =\\ \\\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{1}{2}= \\ \\6+\frac{1}{2}=\\ \\6\frac{1}{2}

8 0
2 years ago
Solve the quadratic in form equation x^4-14x^2+45=0
Anastaziya [24]
X⁴-14x²+45=0
(x²) ²-14x²+45=0
let y=x²
y²-14y+45=0
(y-9) (y-5) =0
y=9 or y=5
x²=9 or x²=5
x=±3 or x=±√5
7 1
3 years ago
Explain how the steps of the distributive property can be used to solve the equation 3(x + 4) =36 ?
Oksanka [162]

Step-by-step explanation:

First, apply the distributive property to the left side of the equation. Multiply each of the two numbers inside the parentheses by 12 and then combine those products. Next, solve as you would solve any two-step equation. To isolate \begin{align*}12x\end{align*} on the left side of the equation, add 24 from both sides.

3 0
3 years ago
Read 2 more answers
Other questions:
  • Fifth roots of 243 cos 2π 3 + i sin 2π 3 (a) use the formula zk = n r cos θ + 2πk n + i sin θ + 2πk n to find the indicated root
    11·1 answer
  • One meter of electrical cord costs 3 dollars. How much should one pay for 4 meters?? Please help me out here.
    9·1 answer
  • A certain species of fish has been declining in population by 7% per year. That means it's rate of decay is 0.93. The population
    10·1 answer
  • 19x^3 + (14x + 4x^3) =
    15·2 answers
  • A movie theater earned $3,600 in sold-out ticket sales for the premiere of a new movie. VIP tickets cost $20 per person and regu
    8·1 answer
  • Slope intercept from y-4=-3(x-3) step by step please
    13·1 answer
  • 4th term <br> c(n) = -7 + 6(n - 1 )
    9·1 answer
  • Angle relationships worksheet #2 10-17
    13·1 answer
  • I need help please ASAP
    7·2 answers
  • Penny has 139 postcards in her collection. Abe has 48 postcards in his collection. Then Abe gives his collection away. He divide
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!