Question

What is the area of this rectangle?

Answer 1

Answer:

The answer to your question is:  40u²

Step-by-step explanation:

Data

Find the vertex

A (-4, 0)

B (-6, 4)

C (2, 8)

D (4, 4)

Formula

d = $\sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }$

Area = base x height

Process

1.- Find the distance from A to B, and the distance from A to D

2.- Obtan the area of the rectangle

1.-

     dAB = $\sqrt{(-6 + 4)^{2} + (4 - 0)^{2} }$

     dAB = $\sqrt{2^{2} + 4^{2} }$

     dAB = $\sqrt{4 + 16}$

     dAB = $\sqrt{20}$

     dAD = $\sqrt{(4 + 4)^{2} + (4 - 0)^{2} }$

     dAD = $\sqrt{8^{2} + 4^{2} }$

     dAD = $\sqrt{64 + 16}$

     dAD = $\sqrt{80}$

2.-

Area = $\sqrt{20} x \sqrt{80}$

Area = $\sqrt{20x80}$

Area = $\sqrt{1600}$

Area = 40u²