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3 years ago

7

Please help for 10 points and i will pick the brainliest . Thankyou

1 answer:

lidiya [134]3 years ago

4 0

23) Store A: y=6.30÷2
y=3.15
Store B: y=3.2
Store C: y=3.25x
y=3.25 so Store A sells the cheapest so (A) is the answer

24) the area uses half of the diameter, not the whole diameter. so the answer is 5.5pi^2 (B)

25) 1/2 × 1/2 = 1/4 × 1/2 = 1/8 (D)

26) was done correctly and (D) is the correct answer

27) 2 (x-3) +1 =19
2 (x-3) = 19 - 1
(x-3) = 18 ÷ 2
x-3 = 9
x= 9+3
x=12 (D)

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Tyree is determining the distance of a segment whose endpoints are A(–4, –2) and B(–7, –7).

PilotLPTM [1.2K]

Answer:

Tyree’s solution is inaccurate. In step 1, he substituted incorrectly.

Step-by-step explanation:

to find the distance between two point A(-4, -2) and B(-7, -7) we use the following distance formula

$d=\sqrt{(x_{2} -x_{1})^2+(y_{2}-y_{1} )^2 \\\\$

x1=-4, x2=-7

y1=-2, y2=-7

so,

$d=\sqrt{(-7-(-4))^2+(-7-(-2) )^2\\}\\\\d=\sqrt{(-7+4)^2+(-7+2)^2 }\\\\d=\sqrt{(-3)^2+(-5)^2 }\\\\\\\\d=\sqrt{9+25}\\ \\d=\sqrt{34}$

4 0

4 years ago

I will give brainliest to the right answer:)

Akimi4 [234]

Answer:

178.1

Step-by-step explanation:

In the first blank, write in 7 for x, and in the second blank, write in 8 for y. Then perform the indicated multiplication and addition.

12.3(7) + 11.5(8), or

86.1 + 92 = 178.1

5 0

3 years ago

Can you help me do the steps for this geometry problems ?

Mrrafil [7]

Yes what problems you need help with

6 0

4 years ago

Find the value of y when x= -12.<br> y=x/2 +9<br>y =

ankoles [38]

Answer:

3 is what I think the answer is

3 0

3 years ago

Find lim h->0 f(9+h)-f(9)/h if f(x)=x^4 a. 23 b. -2916 c. 2916 d. 2925

Svetach [21]

$\displaystyle\lim_{h\to0}\frac{f(9+h)-f(9)}h = \lim_{h\to0}\frac{(9+h)^4-9^4}h$

Carry out the binomial expansion in the numerator:

$(9+h)^4 = 9^4+4\times9^3h+6\times9^2h^2+4\times9h^3+h^4$

Then the 9⁴ terms cancel each other, so in the limit we have

$\displaystyle \lim_{h\to0}\frac{4\times9^3h+6\times9^2h^2+4\times9h^3+h^4}h$

Since <em>h</em> is approaching 0, that means <em>h</em> ≠ 0, so we can cancel the common factor of <em>h</em> in both numerator and denominator:

$\displaystyle \lim_{h\to0}(4\times9^3+6\times9^2h+4\times9h^2+h^3)$

Then when <em>h</em> converges to 0, each remaining term containing <em>h</em> goes to 0, leaving you with

$\displaystyle\lim_{h\to0}\frac{f(9+h)-f(9)}h = 4\times9^3 = \boxed{2916}$

or choice C.

Alternatively, you can recognize the given limit as the derivative of <em>f(x)</em> at <em>x</em> = 9:

$f'(x) = \displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h \implies f'(9) = \lim_{h\to0}\frac{f(9+h)-f(9)}h$

We have <em>f(x)</em> = <em>x</em> ⁴, so <em>f '(x)</em> = 4<em>x</em> ³, and evaluating this at <em>x</em> = 9 gives the same result, 2916.

8 0

3 years ago