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konstantin123 [22]
3 years ago
10

How are the areas of a triangle and a parallelogram with the same base and height related?

Mathematics
1 answer:
kifflom [539]3 years ago
3 0

If a triangle and a parallelogram have the same base
and the same height, then the area of the triangle
is  1/2  of the area of the parallelogram.

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Simplify using appropriate property: 5/7 X 1/5 + 5/7 X 3/5Simplify using appropriate property:
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Answer:

4/7

Step-by-step explanation:

5/7 x (1/5+3/5) = 5/7 x 4/5 = 4/7

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Six and forty-two ten-thousandths as a decimal
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6.0042

Step-by-step explanation:

6 and forty-two ten-thousandths as a decimal.

mixed number : 6\frac{42}{10,000}

decimal : 6.0042

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Write the Roman Numeral for XXVII in standard form.
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The Colossus Ferris wheel debuted at the 1984 New Orleans World’s Fair. The ride is 180 ft tall, and passengers board the ride a
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Answer:

The Colossus Ferris wheel debuted at the 1984 New Orleans World’s Fair. The ride is 180 ft tall, and passengers board the ride at an initial height of 15 ft above the ground. The height above ground, h, of a passenger on the ride is a periodic function of time, t. The graph displays the height above ground of the last passenger to board over the course of the 15 min ride.

Sine function model: where h is the height of the passenger above the ground measured in feet and t is the time of operation of the ride in minutes.

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1. What is the period of the sine function model? Interpret the period you found in the context of the operation of the Ferris wheel.

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Two vertical poles of length 10 and 12 ​feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the
Marat540 [252]

Answer:

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft

Step-by-step explanation:

let length of calble = L

distance from 10-foot pole = x ft

Moving from the top of the 10-foot pole to point x, we have

From the diagram that

x^{2} +10^{2}=L_{1} ^{2}  \\x^{2} + 100 = L_{1} ^{2}

Take the square root of both sides

\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\  \sqrt{x^{2}+100}= L_{1}

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

(17-x)^{2}+12^{2}=L_{2} ^{2}   \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}

Take the square root of both sides

\sqrt{x^{2}-34x+433}=\sqrt{L_{2} ^{2}}  \\\sqrt{x^{2}-34x+433}=L_{2}

Amount of cable used, L = L1 + L2

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