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2 years ago

A. 40, B.80, C.120, D. 160, or E. 400

Mathematics

2 answers:

SpyIntel [72]2 years ago

8 0

ιт ιѕ 80

υиℓιкє ωιтн αяєα ωнєяє υ мυℓтιρℓу ℓєиgтн тιмєѕ ωι∂тн

ωιтн ρєяιмєтєя уσυ ʝυѕт α∂∂ тнєм

Rudik [331]2 years ago

6 0

B: 80

All the sides add up to 20 so adding all four sides make 80

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Mathematical Statement Justification

olya-2409 [2.1K]

Answer:

Step-by-step explanation:

1. Given mathematical statement

$4x+3=x+5-2x$

So,

$\begin{array}{cc}4x+3=x+5-2x&\text{ Given}\end{array}$

2. Rewrite it as

$4x+3=x-2x+5$

So,

$\begin{array}{cc}4x+3=x-2x+5&\text{ Commutative property of addition}\end{array}$

3. Combine like terms $x$ and $-2x:$

$4x+3=-x+5$

So,

$\begin{array}{cc}4x+3=-x+5&\text{ Combine like terms}\end{array}$

4. Add $x$ to both sides:

$4x+3+x=-x+5+x\\ \\5x+3=5$

So,

$\begin{array}{cc}5x+3=5&\text{ Addition property of equality}\end{array}$

5. Subtract 3 from both sides:

$5x+3-3=5-3\\ \\5x=2$

So,

$\begin{array}{cc}5x=2&\text{ Subtraction property of equality}\end{array}$

6. Divide both sides by 5:

$x=\dfrac{2}{5}$

So,

$\begin{array}{cc}x=\dfrac{2}{5}&\text{ Division property of equality}\end{array}$

6 0

2 years ago

Read 2 more answers

in Hanley's school, 0.723 of the students participated in an event. if there are 1000 students in Hanley School, how many partic

Ugo [173]

Answer:

723 students participated in the event

Explanations:

The total number of students in Hanley's school = 1000

0.723 of the students participated in an event

Number of students that participated in the event = 0.723 x 1000

Number of students that participated in the event = 723

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10 months ago

Plzzz help i really need help and WILL GIVE BRAINLIST IF U put them in order

Vaselesa [24]

x, -x,-4, |-1.5|, |5|, |-6|

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2 years ago

Find the first term and the common ratio <br>third term =6 and seventh term= 96

mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: $a_n= a_1r^{n-1}$

We are given: third term = 6 i,e

$a_3=a_1r(3-1)\\6=a_1r^2----eq(1)$

Seventh term = 96

$a_7=a_1r(7-1)\\96=a_1r^6----eq(2)$

Dividing eq(2) and eq(3)

$\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}$

So, Common Ratio r = 2

Finding First term using eq(1)

$a_3=a_1r^2\\6=a_1(2)^2\\6=a_1(4)\\a_1= \frac{6}{4}\\a_1= \frac{3}{2}$

So, First term a₁ = 3/2 and common ratio r = 2

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2 years ago

The graph of f is shown. find and interpret f(45).

Ket [755]

The function represents the number of accidents (f(x)) per 50 million miles driven as a function of the driver's age (x).

$f(x)=0.4x^2-36x+1000$

f(45) indicates that you have to find the value of f(x) when x=45, to do so replace the equation of the function with the value of x and solve for f(x)

$\begin{gathered} f(x)=0.4x^2-36x+1000 \\ f(45)=0.4(45)^2-36\cdot45+1000 \\ f(45)=0.4\cdot2025-1620+1000 \\ f(45)=810-1620+1000 \\ f(45)=190 \end{gathered}$

For x=45 years f(x)=190

f(45)=190; This value indicates that 45-year-old drivers had 190 accidents per 50 million miles driven.

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10 months ago