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klasskru [66]
3 years ago
13

A line l with slope −45 passes through the point (-10, 4). Is the point (-5, 8) on line l?

Mathematics
1 answer:
Lorico [155]3 years ago
7 0
True
hope this helps :)

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What is 32767/32768 as a reduced fraction?
Anit [1.1K]
32,767/32,768 is in lowest terms and can't be reduced.
8 0
3 years ago
There is a hot market at school for used graduation gowns, in fact the price is growing exponentially! Last week I could have go
Daniel [21]

Answer:

$100

Step-by-step explanation:

the equation to solve this is:

y=12.5x+25

y=12.5x+25\\ =(12.5*6)+25\\ =75+25\\ =100

(Assuming, of course, that this is a homework assignment and not you actually buying it cuz' in real life the numbers would be different from month to month)

4 0
3 years ago
Equations<br> Solve T = C(9+ AB) for B
MaRussiya [10]

Answer:

Simplifying

T = C(9 + AB) * forB

Reorder the terms for easier multiplication:

T = C * forB(9 + AB)

Multiply C * forB

T = forBC(9 + AB)

T = (9 * forBC + AB * forBC)

Reorder the terms:

T = (forAB2C + 9forBC)

T = (forAB2C + 9forBC)

Solving

T = forAB2C + 9forBC

Solving for variable 'T'.

Move all terms containing T to the left, all other terms to the right.

Simplifying

T = forAB2C + 9forBC

Step-by-step explanation:

Simplifying

T = C(9 + AB) * forB

Reorder the terms for easier multiplication:

T = C * forB(9 + AB)

Multiply C * forB

T = forBC(9 + AB)

T = (9 * forBC + AB * forBC)

Reorder the terms:

6 0
2 years ago
The average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 in
Murrr4er [49]

Answer:

Probability that average height would be shorter than 63 inches = 0.30854 .

Step-by-step explanation:

We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.

Also, a random sample of 4 women from this population is taken and their average height is computed.

Let X bar = Average height

The z score probability distribution for average height is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 64 inches

           \sigma = standard deviation = 4 inches

           n = sample of women = 4

So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)

P(X bar < 63) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{63-64}{\frac{4}{\sqrt{4} } } ) = P(Z < -0.5) = 1 - P(Z <= 0.5)

                                                        = 1 - 0.69146 = 0.30854

Hence, it is 30.85%  likely that average height would be shorter than 63 inches.

7 0
3 years ago
What is 5/9 +1/3 = I appreciate all answers!!
Allisa [31]
It is false or 8/9 is equal to 1
5 0
3 years ago
Read 2 more answers
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