32,767/32,768 is in lowest terms and can't be reduced.
Answer:
$100
Step-by-step explanation:
the equation to solve this is:


(Assuming, of course, that this is a homework assignment and not you actually buying it cuz' in real life the numbers would be different from month to month)
Answer:
Simplifying
T = C(9 + AB) * forB
Reorder the terms for easier multiplication:
T = C * forB(9 + AB)
Multiply C * forB
T = forBC(9 + AB)
T = (9 * forBC + AB * forBC)
Reorder the terms:
T = (forAB2C + 9forBC)
T = (forAB2C + 9forBC)
Solving
T = forAB2C + 9forBC
Solving for variable 'T'.
Move all terms containing T to the left, all other terms to the right.
Simplifying
T = forAB2C + 9forBC
Step-by-step explanation:
Simplifying
T = C(9 + AB) * forB
Reorder the terms for easier multiplication:
T = C * forB(9 + AB)
Multiply C * forB
T = forBC(9 + AB)
T = (9 * forBC + AB * forBC)
Reorder the terms:
Answer:
Probability that average height would be shorter than 63 inches = 0.30854 .
Step-by-step explanation:
We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.
Also, a random sample of 4 women from this population is taken and their average height is computed.
Let X bar = Average height
The z score probability distribution for average height is given by;
Z =
~ N(0,1)
where,
= population mean = 64 inches
= standard deviation = 4 inches
n = sample of women = 4
So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)
P(X bar < 63) = P(
<
) = P(Z < -0.5) = 1 - P(Z <= 0.5)
= 1 - 0.69146 = 0.30854
Hence, it is 30.85% likely that average height would be shorter than 63 inches.
It is false or 8/9 is equal to 1