What would be the answer to 8x^6/ 8x^5 =?

1 answer:

3 0

In dividing two equation with variables and exponent, First you must align or rearrange the equation and group them base on their variables but don't forget the sign of each variables. Second, proceed in dividing its quantity and then subtract its exponent to the other variables having the same. So by calculating it, the answer would be X or X^1

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2 years ago

Jarrett's puppy weighed 3 3/4 ounces at Birth. At 1 week old, the puppy weighed 5 1/8 ounces. At 2 weeks old, the puppy weighed

Ad libitum [116K]

Answer: The answer is $7\dfrac{7}{8}$ ounces.

Step-by-step explanation: Given in the question the weight of Jarrett's puppy at birth, one week old and 2 weeks old are as follows:

$b_0=3\dfrac{3}{4}=\dfrac{15}{4}~\textup{ounces},\\\\\\b_1=5\dfrac{1}{8}=\dfrac{41}{8}~\textup{ounces},\\\\\\b_3=6\dfrac{1}{2}=\dfrac{13}{2}~\textup{ounces}.$

We can see that

$b_1-b_0=b_2-b_1=\dfrac{11}{8}.$

So, the weight of the baby will make an arithmetic progression with first term 'a' and common difference 'd' as follows:

$b_0=\dfrac{15}{4},~~d=\dfrac{11}{8}.$

Thus, the weight of the puupy after 3 weeks will be

$b_3=b_0+3\times d=\dfrac{15}{4}+3\times\dfrac{11}{8}=\dfrac{30+33}{8}=\dfrac{63}{8}=7\dfrac{7}{8}~\textup{ounces}.$

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3 years ago

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