Question

Make c the subject of p=c2/c2+4

Answer 1

$p= \dfrac{c^2}{c^2 + 4}$

$c^2 p + 4 p = c^2$

$4 p = c^2 - c^2 p = c^2(1-p)$

$c^2 = \dfrac{4p}{1-p}$

$c = \pm \sqrt{\dfrac{4p}{1-p} } = \pm 2 \sqrt{\dfrac{p}{1-p} }$

Answer: $\quad c = \pm 2 \sqrt{\dfrac{p}{1-p}$