$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}(x-6)^{n+1}}{4n+5}}{\frac{(-1)^n(x-6)^n}{4n+1}}\right|=|x-6|\lim_{n\to\infty}\left|\frac{4n+1}{4n+5}\right|=|x-6|$

The series converges for

$|x-6|$

which has a radius of convergence of 1.

3 0

3 years ago

What is the DOMAIN of this relation? Write your answer.

pashok25 [27]

Answer: Domain = {-4, -1, 0, 2, 7, 8, 13}

The domain is the set of allowed x inputs. So all we do is list the set of x values in the top row of the table.

In contrast, the range is the set of possible y outputs. So the range would be {5,2,-3,7,4,9}. Any duplicate items in the range are tossed out. Optionally you can order the set from smallest to largest, but that's not required. This is because order in a set doesn't matter.

6 0

2 years ago

Read 2 more answers

Ken saves $140 per month. If this is 2.5% of his monthly income, how much does he earn per month?

frozen [14]

Multiple $140 with 100% and divide the result with 2.5%
the answer is 5,600

5 0

2 years ago