Answer:
Im pretty sure its A. 83%
Step-by-step explanation:
Answer:
y=3x+18
Step-by-step explanation:
Since slope-intercept form is y=mx+b, we first need to find the slope.
m=y2-y1/x2-x1
m=0-(-9)/-6-(-9)
m=9/3=3
Next we need to find b, or the y-intercept
to do that we plug in numbers to what we already have.
y=3x+b
0=-18+b
b=18
Now we put it all together.
<h3>y=3x+18</h3>
Answer:
poopppppppppppppppppppppeeeee
Answer:
The mother (Rhoda) is 46 years old.
The daughter (Tenica) is 18 years old
Step-by-step explanation:
Let the age of the mother (Rhoda) be m
Let the age of the daughter (Tenica) be d.
The sum of Rhonda and her daughter Tenica’s age is 64. This can be written as:
m + d = 64 ... (1)
The difference in their ages is 28. This can be written as:
m – d = 28 ... (2)
From the above illustrations, the equation obtained are:
m + d = 64 ... (1)
m – d = 28 ... (2)
Solving by elimination method:
Add equation 1 and 2 together
. m + d = 64
+ m – d = 28
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
2m = 92
Divide both side by 2
m = 92/2
m = 46
Substitute the value of m into any of the equation to obtain the value of d. Here, we shall use equation 1
m + d = 64
m = 46
46 + d = 64
Collect like terms
d = 64 – 46
d = 18
Therefore, the mother (Rhoda) is 46 years old and the daughter (Tenica) is 18 years old.
Answer: The mean number of checks written per day ![=0.3452](https://tex.z-dn.net/?f=%3D0.3452)
Standard deviation![=0.5875](https://tex.z-dn.net/?f=%3D0.5875)
Variance ![=0.3452](https://tex.z-dn.net/?f=%3D0.3452)
Step-by-step explanation:
Given : The total number of checks wrote by person in a year = 126
Assume that the year is not a leap year.
Then 1 year = 365 days
Let the random variable x represent the number of checks he wrote in one day.
Then , the mean number of checks wrote by person each days id=s given by :-
![\lambda=\dfrac{126}{365}\approx0.3452](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B126%7D%7B365%7D%5Capprox0.3452)
Since , the distribution is Poisson distribution , then the variance must equal to the mean value i.e. ![\sigma^2=\lambda=0.3452](https://tex.z-dn.net/?f=%5Csigma%5E2%3D%5Clambda%3D0.3452)
Standard deviation : ![\sigma=\sqrt{0.3452}=0.5875372328\approx0.5875](https://tex.z-dn.net/?f=%5Csigma%3D%5Csqrt%7B0.3452%7D%3D0.5875372328%5Capprox0.5875)