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Gwar [14]
4 years ago
7

At Tony and Cleo’s bakery, one kind of birthday cake is offered. It takes 15 minutes to decorate this particular cake, and the j

ob is performed by one particular baker. In fact, it is all this baker does. What mean time between arrivals (exponentially distributed) can be accepted if the mean length of the queue for decorating is not to exceed five cakes?
Business
1 answer:
Ugo [173]4 years ago
8 0

Answer:

Explanation:

Average length of queue, Lq = λ^2/μ/(μ-λ)

μ is service rate, λ is arrival rate

Mean time to service = 15 minutes  (decoration)

Service rate, μ = 60 / 15 = 4 per hour

 

It is given that the mean length of the queue for decorating is not to exceed five cakes, Lq = λ^2/μ/(μ-λ) = 5

λ^2/4/(4-λ) = 5

λ = 3.4164 per hour

Mean time between arrivals = 60 / 3.4164 = 17.56 minutes

The minimum acceptable mean time between arrivals = 17.56 minutes

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Answer:

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Explanation:

When an general environmental analysis is done by a company , they expect to identify what elements ( whether it be external or internal ), can have an impact on the performance of the company. The purpose of this strategy tool is to see what opportunities are present in the market which a company can use for its advantage( for increasing sales or expansion) and also to identify what level of threats are present in the market that can affect their profitability and market share.

By doing environmental analysis they can see what products or services are trending in the market, what is the general peoples tastes and preferences, so we can say that the options b,c,d are all correct, therefore the option a is incorrect.

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