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Gwar [14]
4 years ago
7

At Tony and Cleo’s bakery, one kind of birthday cake is offered. It takes 15 minutes to decorate this particular cake, and the j

ob is performed by one particular baker. In fact, it is all this baker does. What mean time between arrivals (exponentially distributed) can be accepted if the mean length of the queue for decorating is not to exceed five cakes?
Business
1 answer:
Ugo [173]4 years ago
8 0

Answer:

Explanation:

Average length of queue, Lq = λ^2/μ/(μ-λ)

μ is service rate, λ is arrival rate

Mean time to service = 15 minutes  (decoration)

Service rate, μ = 60 / 15 = 4 per hour

 

It is given that the mean length of the queue for decorating is not to exceed five cakes, Lq = λ^2/μ/(μ-λ) = 5

λ^2/4/(4-λ) = 5

λ = 3.4164 per hour

Mean time between arrivals = 60 / 3.4164 = 17.56 minutes

The minimum acceptable mean time between arrivals = 17.56 minutes

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How does a magazine sustain the alternating interests of readers who on account of life issues are moving on to the next segment
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3 years ago
Travis International has a one-time expense of $2.86 million that must be paid three years from now. Since the firm cannot raise
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monthly saving  = $77037.69

Explanation:

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we find here monthly saving  by formula that is

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