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VashaNatasha [74]
4 years ago
6

Which of the following OSI layers is responsible for the segmentation, multiplexing, flow control and host-to-host communication

services for applications?
- Presentation Layer
- Network Layer
- Transport Layer
- Session Layer
- Datalink Layer
Computers and Technology
1 answer:
mariarad [96]4 years ago
8 0

Answer:

Transport Layer

Explanation:

  • Transport Layer is responsible for host-to-host communications of applications.
  • OSI model has seven layers while other models like TCP/IP has four layers.
  • OSI model stands for Open Systems Interconnection.
  • The seven layers of OSI model architecture are the following starting from the Hardware Layers ( Layers in Hardware Systems ) to Software Layers ( Layers in Software Systems )
  1. Physical Layer
  2. Data link Layer
  3. Network Layer
  4. Transport Layer
  5. Session Layer
  6. Presentation Layer
  7. Application Layer
  • Each layer has its unique functionality which is responsible for the proper functioning of the communication services.
  • Transport Layer is responsible for multiplexing, segmentation, flow control and host-to-host communication services.
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3 years ago
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kherson [118]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

   

    double balance, rate, interest;

   

 System.out.print("Enter the balance: ");

 balance = input.nextDouble();

 

 System.out.print("Enter the annual percentage interest rate [%4.25 must be entered as 4.25]: ");

 rate = input.nextDouble();

 

 if(balance < 0 || rate < 0)

     System.out.println("The balance and/or interest rate cannot be negative!");

 else{

     interest = balance * (rate / 1200);

     System.out.printf("The interest amount $%.2f", interest);

 }

}

}

Explanation:

Ask the user to enter the balance

Ask the user to enter the interest rate as given format

Check the balance and rate. If any negative value is entered, print an error message. Otherwise, calculate the interest using the given formula and print the interest in required format

3 0
3 years ago
Determine the distance between point (x1, y1) and point (x2, y2), and assign the result to points Distance. The calculation is:
Nadusha1986 [10]

<u>Question:</u>

Snapshot of the question has been attached to this response.

<u>Answer:</u>

<u></u>

import java.util.Scanner;

import java.lang.Math;

public class CoordinateGeometry{

    public static void main(String []args){

       double x1 = 1.0;

       double y1 = 2.0;

       double x2 = 1.0;

       double y2 = 5.0;

       double pointsDistance = 0.0;

       

       //Declare a variable to hold the result of (x2 - x1)²

       double x;

       

       //Solve (x2 - x1)^2 and store result in the variable x

       x = Math.pow(x2 - x1, 2);

       

       //Declare a variable to hold the result of (y2 - y1)²

       double y;

       

       //Solve (y2 - y1)^2 and store result in the variable y

       y = Math.pow(y2 - y1, 2);

       

       //Now pointsDistance = SquareRootOf(x + y)

       pointsDistance = Math.sqrt(x + y);

       

       System.out.println("Points distance: ");

       System.out.println(pointsDistance);

       

       return;

    }

}

<u>Sample Output:</u>

Points distance:  

3.0

<u>Explanation:</u>

The above code has been written in Java and it contains comments explaining important lines of the code. Please go through the comments.

The snapshots of the program and a sample output have been attached to this response.

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Answer:

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