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harkovskaia [24]
4 years ago
12

F(x)=x^2. what is g(x)? NEED ASAP WILL MARK BRAINLIEST

Mathematics
1 answer:
Bess [88]4 years ago
6 0

Answer:

g(x)= \frac{1}{9} \times x^2

Step-by-step explanation:

Here we can see that the parent function is f(x)=x^2 and the translated function is g(x). f(x) is a parabola.

Rule says that any factor if multiplied by f(x) is going to contract the graph towards the y axis and vice versa.

Similarly any factor if  f(x) is divided by some factor it is going to be stretch the graph away from the y axis and vice versa.

Here we can see that the translated graph g(x) is stretched away from the y axis with reference to the parent function f(x). Hence as per he rule discussed above, we get a preliminary information that the parent function f(x) is being divided by some factor.

now we are given that

f(x) = x^2

f(3) = 3^2 = 9

Where as

g(3) = 1  {as given in the graph}

Hence

at x=3 , f(x) = 9 and g(x) = 1 , and also we have discussed above that f(x) is divided by some factor. Hence g(x)= \frac{1}{9}f(x)

g(x)= \frac{1}{9} \times x^2

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2 years ago
The extract of a plant native to Taiwan has been tested as a possible treatment for Leukemia. One of the chemical compounds prod
masya89 [10]

Answer:

a) 0.2578 = 25.78% probability that the amount of collagen is greater than 60 grams per mililiter.

b) 0.9994 = 99.94% the probability that the amount of collagen is less than 90 grams per mililiter.

c) 68.26% of compounds formed from the extract of this plant fall within 1 standard deviation of the mean

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The collagen amount was found to be normally distributed with a mean of 65 and standard deviation of 7.7 grams per mililiter.

This means that \mu = 65, \sigma = 7.7

a. What is the probability that the amount of collagen is greater than 60 grams per.

This is 1 subtracted by the pvalue of Z when X = 60. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 65}{7.7}

Z = -0.65

Z = -0.65 has a pvalue of 0.2578

0.2578 = 25.78% probability that the amount of collagen is greater than 60 grams per mililiter.

b. What is the probability that the amount of collagen is less than 90 grams per.

This is the pvalue of Z when X = 90.

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 65}{7.7}

Z = 3.25

Z = 3.25 has a pvalue of 0.9994

0.9994 = 99.94% the probability that the amount of collagen is less than 90 grams per mililiter.

c. What percentage of compounds formed from the extract of this plant fall within 1 standard deviation of the mean?

Between Z = 1 and Z = -1, so the proportion is the pvalue of Z = 1 subtracted by the pvalue of Z = -1

Z = 1 has a pvalue of 0.8413

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

0.6826*100% = 68.26% of compounds formed from the extract of this plant fall within 1 standard deviation of the mean

8 0
3 years ago
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