Answer:
88
Step-by-step explanation:
4 sin(<em>x</em>) + 9 cos(<em>x</em>) = 0
4 sin(<em>x</em>) = -9 cos(<em>x</em>)
tan(<em>x</em>) = -9/4
<em>x</em> = arctan(-9/4) + <em>nπ</em> … … … (in radians)
or
<em>x</em> = arctan(-9/4) + 180<em>n</em> ° … … … (in degrees)
where <em>n</em> is any integer.
I'm guessing you're solving for <em>x</em> over some domain, probably 0° ≤ <em>x</em> < 360°. In that case, you would have two solutions for <em>n</em> = 1 and <em>n</em> = 2 of
<em>x</em> ≈ 113.96° and <em>x</em> ≈ 293.96°
Answer:
16 quarts
Step-by-step explanation:
Let's say x is the volume of water.
Initially, the amount of antifreeze is the concentration times the volume: 0.90 (8).
After the water is added, the amount of antifreeze is the new concentration times the new volume: 0.30 (8 + x).
Since the amount of antifreeze doesn't change, we can set these equal and solve for x.
0.90 (8) = 0.30 (8 + x)
7.2 = 2.4 + 0.30 x
4.8 = 0.30 x
x = 16
16 quarts of water should be added.
First, we subtract 12x from both sides. We then get -4y=-12x+48. We then divide this by -4 on both sides to get the y by itself. We then get that the equation is y=3x-12.
137 1/4 sq ft or the measurement
