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poizon [28]
4 years ago
7

Consider today's stock listing for Enam Telecom, shown below. 52 wk High 52 wk Low Symbol Div. Close Net Change 122.86 64.77 ENM

3.45 99.14 4.74 If the lowest price in the past year occurred 48 days ago, find the approximate average change per day since then. a. $4.74 b. $0.72 c. $0.49 d. $1.34
Mathematics
1 answer:
docker41 [41]4 years ago
3 0

Answer:

B. $0.72

Step-by-step explanation:

Here is the stock listing for Enam Telecom

52 wk high is 122.86

52 wk low is 64.77

Div. is 3.45

Close is 99.14

Net change is 4.74

From the question the lowest price which was 64.77 was 48 days ago.

therefore net change in value is:

Close - lowest price:

99.14 - 64.77 = 34.37

Since change is in 48 days,

the average change per day is:

Total change / number of days = 34.37/48 = 0.716

This answer is approximately 0.72

Therefore average change per day is 0.72

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Find the value of the expression 0.5^10/0.5^7
SIZIF [17.4K]

Answer:

The solution is:

  • \frac{0.5^{10}}{0.5^7}=0.125

Step-by-step explanation:

Given the expression

0.5^{10}\div 0.5^7

Solving

\frac{0.5^{10}}{0.5^7}

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}

so

\frac{0.5^{10}}{0.5^7}=0.5^{10-7}

\mathrm{Subtract\:the\:numbers:}\:10-7=3

=0.5^3

=0.125        ∵ 0.5^3=0.125

Therefore, the solution is:

\frac{0.5^{10}}{0.5^7}=0.125

7 0
3 years ago
What is the simplified form of the following expression? 7 (RootIndex 3 StartRoot 2 x EndRoot) minus 3 (RootIndex 3 StartRoot 16
11111nata11111 [884]

Answer:

c

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
An insurance company insures red and green cars. An actuary compiles the following data: Color of car Red Green Number insured 3
julsineya [31]

Answer:

2.7%

Step-by-step explanation:

Since the probability of having and accident or exceed the deductible does not depend on the color of the car, the events are independent.

Recall that if two events A and B with probabilities P(A), P(B) of occurrence are independent, then

P(A ∩ B) = P(A)P(B)

There is a 300/1000 = 0.3 probability of choosing a random car. So, if the actuary randomly picks a claim from all claims that exceed the deductible,the probability that the claim is on a red car is

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Vanyuwa [196]

Answer:

x=10

Step-by-step explanation:

1/2x-2+3

      +2  +2

1/2x=5

----   ---

1/2   1/2

x=10

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4 years ago
There are 87 green balls and 41 red balls in a bag. If one is randomly selected, what is the probability that it will be a green
garri49 [273]

Number of green balls = 87

Number of red balls = 41

So total number of balls = 128

Probability formula = number of events / number of possible outcomes.

So, the probability that a ball randomly selected will be a green ball will be

\frac{87}{87+41}

equals 0.6796875 converting to nearest hundredth as 0.68


5 0
3 years ago
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