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Inessa [10]
3 years ago
6

8. A candle is 4 inches tall and burns at the rate of 0.6 inch per hour. If the height of the candle after x hours is 1.5 inches

,
write an equation to represent the situation. Then use this equation to find the expected number of hours in which the candle
melted to 1.5 inches.
Mathematics
1 answer:
Ronch [10]3 years ago
3 0

Answer with Step-by-step explanation:

A candle is 4 inches tall and burns at the rate of 0.6 inch per hour.

i.e. after 1 hour height of candle=4-0.6 inches

After 2 hours height of candle=4-0.6-0.6 inches

after x hours height of candle=4-0.6x

Also,

If the height of the candle after x hours is 1.5 inches

⇒  4-0.6x=1.5

⇒ 0.6x=4-1.5

⇒ 0.6x=2.5

⇒ x=2.5/0.6

⇒ x=4.166

Hence, equation to represent the situation. is:

4-0.6x=1.5

and the expected number of hours in which the candle  melted to 1.5 inches is:

4.166 hours

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krek1111 [17]
Ratio- 3: 2

3x + 2x = 150
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x = 30

3x is the larger number so plug in the x value with 30.

3x
3 x 30
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The larger number is 90.

Hope I helped.. ^^
8 0
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neonofarm [45]
Since this is a linear function, filling in the minimum and maximum of the domain is sufficient.

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3 years ago
While driving from​ Chicago, Brent had a visibility problem due to the fog. After 1 1/2
liq [111]
1) Let x be the original speed that he was driving; 

x mph ---> 1.5 hours 
x+44 mph --> 2.5 hours 

1.5x + 2.5(x+44)=206 
1.5x+2.5x+110=206 
4x=206-110 
4x=96 
x=24 
Therefore, he was travelling at 24 mph in the fog. 

2) Let x be the speed of 1 snail, 
The other snail travels at the speed of x+1 cm/min 

23x+23(x+1)=391 <-- solve for x 
23x+23x+23=391 
46x=368 
x=368/46 
x=8 

Therefore one of the snail travels at 8 cm/min while the other goes at 9 cm/min 

7) Let x be one crew 
Then the other crew would be working at x+0.5 

3.2x+3.2(x0.5)=8 <-- solve for x 
3.2x+1.6x=8 
4.8x=8 
x=8/4.8 
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5 0
4 years ago
R
wolverine [178]

Answer:

Ivy is 6 years old and Rose is 12 years old.

Step-by-step explanation:

To solve this problem, two variables are necessary since we have two unknown variables: Ivy's age and Rose's age.

Ivy's age will be x

and Rose's age will be y

"Ivy is half as old as her sister":

x=\frac{y}{2}

this will be our <u>fist equation.</u>

"In six years, Ivy will be two-thirds as old as Rose"

in six years Ivy will have x+6 years, and Rose will have y +6 years, so for this sentence we have the equation:

x+6=\frac{2}{3}(y+6)

this will be our <u>second equation.</u>

Substituting the value of x from the first equation into the second, and solving for y(Rose):

\frac{y}{2}+6=\frac{2}{3} (y+6)\\\frac{y+12}{2} =\frac{2}{3} (y+6)\\y+12=\frac{4}{3} (y+6)\\3(y+12)=4(y+6)\\3y+36=4y+24\\36-24=4y-3y\\12=y

Rose is 12 years old.

and Ivy (using the fist equation):

x=\frac{12}{2}=6

Ivy is 6 years old.

6 0
3 years ago
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