Answer:
e. all of the above mechanisms for establishment of the microbiota in newborns
Explanation:
To a greater or lesser extent, all of the above contribute to the development of a newborn's microbiota.
The concept here is that the baby is immersed in a novel environment. It implies that any minimal interaction or physical contact can lead to the conditioning of the microbiota depending on that environment.
Also to clarify, there is not only one microbiote. There is a digestive, an intestinal, pulmonary, etc...
A theory is an idea that has yet to be proven by experimentation. A law is a theory that has been proven correct.
HUMAN CAUSES
human population increasing
Destruction of Habitat
Pollution of any sort
<span>global Warming
NATURAL CAUSES
</span><span>climatic cooling and heating
</span><span>changes in sea levels </span>
Answer: Swimming
Explanation:
The swimming motility is one of the type of bacterial movement. This bacterial movement is mediated by the rotating flagella. It takes place when the individual cells move in the liquid environment.
The phase contrast microscope is used to the enhance the contrast of the images formed by the ordinary light microscope. This can be used for observing the transparent and colorless specimens. The phase contrast microscope enables the visualization of the cells and their organelles that would be difficult to observe under the ordinary light microscope.
The phase contrast microscope can also help in observing the swimming motility of the bacteria. This can be used to observe the change in directions of the bacilli under microscope.
Answer
After inland population after migration allele frequency is 0.62 or 62%
Explanation:
Given,
Coastal striped phenotype freq. = 0.22
ss = 0.22

= 0.22
Similarly, inland striped phenotype freq. = 0.43
= 0.43

=
= 0.4690
= 0.47 i.e. 47%

= 0.655
= 0.66 i.e. 66%
the migration range (m) is given as 20%
m= 0.2
allele freq. after migration = pre migration + ∆q
here,
∆q = change in the allele frequency
or
migration of allele freq. from coastal to inland
=
= 0.2 (0.47 – 0.66)
=
= - 0.0382
∆q = -0.04 i.e. 4%