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3 years ago

What is the value of y in the equation 2(2y − 12) = 0? 4 6 7 8

1 answer:

Elena-2011 [213]3 years ago

4 0

First you distribute making it 4y-24=0
second you isolate the variable making it 4y=24
finally you divide by four giving you the answer of y=6

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2(5m^4n^-1)^3 simplify show work please

dangina [55]

Answer:

$\large\boxed{2(5m^4n^{-1})^3=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}}$

Step-by-step explanation:

$\text{Use}\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\-------------------\\\\2(5m^4n^{-1})^3=2(5)^3(m^4)^3(n^{-1})^3=2(125)m^{3\cdot4}n^{-1\cdot3}=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}$

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3 years ago

the length of a rectangle is four times its width. the rectangle has an area of 1024cm^2 work out the width of the rectangle

olga2289 [7]

The width is 16 so the length is 64 (TO clarify W=16)

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7 0

3 years ago

Read 2 more answers

Please help!! I don't get this.

Lynna [10]

The answer to question 5 is -3.
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3 0

2 years ago

Three consecutive integers have a sum of 42. find the integers.

ioda

The answer is 13,14,15.

6 0

3 years ago

3. Find two possible lengths for CD if C, D, and E

Kaylis [27]

Given :

C, D, and E are col-linear, CE = 15.8 centimetres, and DE= 3.5 centimetres.

To Find :

Two possible lengths for CD.

Solution :

Their are two cases :

When D is in between C and E .

. . .

C D E

Here, CD = CE - DE

CD = 15.8 - 3.5 cm

CD = 12.3 cm

When E is in between D and C.

. . .

D E C

Here, CD = CE + DE

CD = 15.8 + 3.5 cm

CD = 19.3 cm

Hence, this is the required solution.

3 0

3 years ago