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Slav-nsk [51]
3 years ago
13

The equation D=13/v shows that the density of a particular substance equals a mass of 13 grams divided by the volume of the subs

tance. What happens to the density as the volume approaches 0?
The density approaches infinity.
The density approaches 0.
The density approaches 1.
The density approaches 13.
Mathematics
2 answers:
lions [1.4K]3 years ago
8 0
For this case we have the following equation:
 D =  \frac{13}{v}
 Where,
 D: t<span>he density of a particular substance 
 v: </span><span> the volume of the substance
 </span>When replacing v = 0 in the given equation we have:
 D = \frac{13}{0}
 D =  \infty
 This means that as the function acquires values very close to zero, the density acquires a very large value.
 Answer:
 
as the volume approaches 0:
<span> The density approaches infinity.
</span> option 1<span>
</span>
katen-ka-za [31]3 years ago
8 0
As the volume approaches 0,
The density approaches infinity

The graph of the equation is a hyperbola with the asymptote at v = 0. This means that when the value of v is very close to 0, the value of the density is very large.
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