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Anastaziya [24]
3 years ago
11

Evaluate (c- 62) + a3 for a = -3,6 = -2, and C = -4.

Mathematics
1 answer:
Crazy boy [7]3 years ago
5 0

Answer:

this is a incomplete math problem and you confused me when you said 6=-2???

Step-by-step explanation:

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Write and solve the equations. A number y is five less than thirteen.
Genrish500 [490]

We can follow the following steps to make an equation and solve it.

Step 1:

five less than 13 means we have to subtract 5 from 13

so it becomes 13-5

Step 2:

A number y is five less than thirteen.

Now in algebraic expressions, "is" stands for "="

So we have:

y=13-5

Step 3:

Solving the equation to find y.

y=13-5

Subtracting 5 from 13, we get :

y=8

Answer:

For the given equation the solution is y=8.

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What movie should i watch on netflix (im a tween and allowed to watch gore)​
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3 years ago
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A, B and C are points on a circle with a diameter AB
Tamiku [17]

Answer:

36.575

Step-by-step explanation:

you need to find line ab you can do A^{2} +B^{2} =C^{2}  for the triangle and get the line you also need to get the squar root of it as it is still squared then devide by 2 to get the rades then times that by pi and there you go you have the area also sorry for spelling I love math not English

3 0
3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
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Tom counted the number of cards in his collection for 10 weeks. By week 5, he had collected 12 cards. This graph shows this info
Karolina [17]

Answer:

i think it would be 17

Step-by-step explanation:

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3 years ago
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