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n200080 [17]
3 years ago
14

Calculate the centripetal force on a 4.5 kg sensor that is attached at the end of a 90.0-m long wind turbine blade that is rotat

ing at 1.00 rev/s.
Physics
1 answer:
ad-work [718]3 years ago
6 0

15972.55N

Explanation:

Given parameters:

Mass of sensor = 4.5kg

length of the turbine blade = 90m

angular velocity = 1 rev/s

Unknown:

Centripetal force = ?

Solution;

Centripetal force is the force that acts on a body moving in a radial form directed towards the center.

It is mathematically expressed as:

   F = \frac{mv^{2} }{r}

m is the mass  

  r is the radius of path

  v is the velocity

  v = wr

w is the angular velocity

 v = 1 x 2πrad x 90 = 565.2m/s

  F = \frac{4.5 x 565.2^{2} }{90}  =15972.55N

learn more:

Force brainly.com/question/8590524

#learnwithBrainly

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If you install special sound-reflecting windows that reduce the sound intensity level by 30.0 db , by what factor have you reduc
shusha [124]

Answer: The sound intensity was reduced by -14.77 dB.

Explanation:

The level of the intensity of the sound with respect to the reference value is called Sound Intensity level.

L_I=10\log\frac{I}{I_o} dB

I = Intensity of the sound

I_o = Reference sound intensity

According to question, sound-reflecting windows that reduce the sound intensity level by 30.0 db .

Let the intensity of the sound be I_o and reduced intensity be I.

I=\frac{I_o}{30} dB

L_I=10\log\frac{I}{I_o} dB

L_I=10\log\frac{\frac{I_o}{30}}{I_o}=10\log\frac{1}{30} dB=-14.77 dB

The sound intensity was reduced by -14.77 dB.

3 0
4 years ago
The movement or spinning of this subatomic particle is what creates magnetism.
Alborosie

Answer:

c electrons

Explanation:

3 0
3 years ago
Read 2 more answers
Neptunium. In the fall of 2002, scientists at Los Alamos National Laboratory determined that the critical mass of neptunium-237
Paladinen [302]

Answer:

Radius = 9.0216 cm

Explanation:

Given that:

The critical mass of neptunium-237 = 60 kg

Also, 1 kg = 1000 g

So mass = 60000 g

Density = 19.5 g/cm³

Volume = ?

So, volume:  

Volume=\frac {{Mass}}{Density}  

Volume=\frac {60000\ g}{19.5\ g/cm^3}  

The volume of the material = 3076.92308 cm³

The expression for the volume of the sphere is:

V=\frac {4}{3}\times \pi\times {(radius)}^3

3076.92308=\frac{4}{3}\times \frac{22}{7}\times {(radius)}^3

\frac{4}{3}\times \frac{22}{7}\times {(radius)}^3=3076.92308

88\times {(radius)}^3=64615.38468

{(radius)}=\sqrt[3]{\frac{64615.38468}{88}}

<u>Radius = 9.0216 cm</u>

4 0
4 years ago
Discuss the law of conservation of energy. Provide at least one example that supports your description.
stich3 [128]
<span> the </span>law of conservation of energy<span> states that the total </span>energy<span> of an isolated system remains constant it would be  said to be conserved over time. </span>Energy<span> can neither be created nor destroyed but then rather, it transforms from one form to another.

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3 0
3 years ago
The Achilles tendon connects the muscles in your calf to the back of your foot. When you are sprinting, your Achilles tendon alt
lesantik [10]

Answer:

(a) \triangle l=5 mm

(b) 0.033

Explanation:

(a)

Force F=mg where m is mass and g is acceleration due to gravity whose value is taken as 9.81 m/s^{2}

However, for this case, the maximum force is 8 times the weight of runner hence F=8mg

Assume Young's modulus for tendon is 0.15*10^{10} N/m^{2}

Young's modulus is given by

E=\frac {Fl}{A\triangle l} and \triangle l=\frac {Fl}{EA} and substituting F with 8mg we obtain \triangle l=\frac {8mgl}{EA}

Where E is young's modulus, l is stretched length and \triangle l is change in length

Substituting m as 70 kg, g as 9.81 m/s^{2}, l as 15cm=0.15 m, E as 0.15*10^{10} N/m^{2} and A as 110 m^{2}=0.000110 m^{2}

\triangle l=\frac {8*70 Kg*9.81 m/s^{2}*0.15m}{0.15*10^{10} N/m^{2} *0.00011 m^{2}}=0.004994182 m

\triangle l=5 mm

(b)

Strain, \epsilon=\frac {\triangle l}{l} and the fraction of tendon’s length is the ratio of change in length to the stretched length

The fraction of tendon, f is given by

f=\frac {\triangle l}{l}. Substituting \triangle l with 0.005m and l with 0.15m we obtain

\epsilon=f=\frac {0.005}{0.15}=\frac {1}{30}=0.033

Therefore, fraction of the tendon’s length is 0.033

5 0
4 years ago
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