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4 years ago

0.05 is 1/10 value of what number

Mathematics

1 answer:

Ivanshal [37]4 years ago

8 0

Answer:

1/2=x

0.5

Step-by-step explanation:

x will be the number

5/100=(1/10)x

5/10=x

1/2=x

1/2=0.5

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Manufacture of a certain component requires three different machining operations. Machining time for each operation has a normal

faust18 [17]

Answer:

The probability is $P(X \le 70) = 0.9685$

Step-by-step explanation:

From the question we are told that

The mean values is $M_1 = 15 \ minutes , \ M_2 = 30\ minutes, \ M_3 = 20 \ minutes$

The standard deviation is $\sigma_1 = 1 \ minutes , \ \sigma_2 = 2 \ minutes , \ \sigma = 1.5 \ minutes$

Generally the total mean is mathematically represented as

$\= x = \sum M_i$

=> $\= x = 15 + 30 + 20$

=> $\= x = 65$

Generally the total variance is mathematically represented as

$V(x) = \sum \sigma^2_i$

=> $V(x) = 2^2 + 1^2 + 1.5^2$

=> $V(x) = 7.25$

Generally the total standard deviation is mathematically represented as

$\sigma = \sqrt{V(x)}$

=> $\sigma = \sqrt{7.25 }$

=> $\sigma = 2.69$

Generally the probability that it takes at most 70 min of machining time to produce a randomly selected component is mathematically represented as

$P(X \le 70) = 1 - P( X > 70 )$

Here $P(X > 70) = P(\frac{X - \mu }{\sigma} > \frac{70 - 65}{ 2.69} )$

$\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )$

$P(X > 70) = P(Z > 1.8587 )$

From the z table

The area under the normal curve to the right corresponding to 1.8587 is

$P(Z > 1.8587 ) = 0.031535$

$P(X \le 70) = 1 - 0.031535$

=> $P(X \le 70) = 0.9685$

7 0

3 years ago

a square is constructed on side AD of quadrilateral ABCD such that FA lies on AB, as shown in the figure. If AD:AB=2:5, the coor

vesna_86 [32]

Answer:2:3

Step-by-step explanation:

8 0

3 years ago

Which statement best compared the graphs

AleksandrR [38]

Answer is D it moves 8 to the right and up 4

3 0

3 years ago

Four glasses of milk and 3 snack bars have a total of 82 carbohydrates (carbs), and 2 glasses of milk and 4 snack bars have a to

vredina [299]

Answer:

milk: 10 carbs
snack bar: 14 carbs

Step-by-step explanation:

Let m and s represent the carbs in the milk and snack bar, respectively. The given relations are ...

4m +3s = 82

2m +4s = 76

Subtracting the first equation from twice the second gives ...

2(2m +4s) -(4m +3s) = 2(76) -(82)

5s = 70 . . . . . . . simplify

s = 14 . . . . . . . divide by 5

We substitute this into the second equation to find m.

2m +4(14) = 76

m +28 = 38 . . . . divide by 2

m = 10 . . . . . . subtract 28

There are 10 carbs in a glass of milk; 14 carbs in a snack bar.

3 0

2 years ago

1. Find the slope of the line that passes through the points (-3, -5) and (3, 2).

Veseljchak [2.6K]

$(-3, -5), \ \ (3, 2) \\ \\ Slope Formula : \\ \\ m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\ \\m=\frac{ 2-(-5)}{ 3-(-3)}\\\\ m=\frac{ 2+5}{ 3+3}\\\\m=\frac{7}{6}$

7 0

3 years ago

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