The perimeter of a rectangle is 44 ft. the length is 6 ft longer than the width. find the dimensions. write a system of linear e quations and solve the resulting system. let x be the length and y be the width.
1 answer:
X= length= y+6 y= width P= perimeter P= 2x + 2y 44= 2(y+6) + 2y 44= 2y + 12 + 2y 44= 4y + 12 subtract 12 from both sides 32= 4y divide both sides by 4 8 ft= y Substitute y=8 to find x 44= 2x + 2y 44= 2x + 2(8) 44= 2x + 16 subtract 16 from both sides 28= 2x divide both sides by 2 14 ft= x ANSWER: Length is 14 feet and width is 8 feet. Hope this helps! :)
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