The 2-point form of the equation of a line is
.. y = (y2 -y1)/(x2 -x1)*(x -x1) +y1
For your points (x1, y1) = (0, 3) and (x2, y2) = (3, 5), this is
.. y = (5 -3)/(3 -0)*(x -0) +3
.. y = (2/3)x +3
Written as a function, it is
.. f(x) = (2/3)x +3
The answer is (4/9)^11 since it is addition you add the powers however the fraction has to be the same in order for it to work same for division but division is subtraction
Well i got 130.
hope it helps : )
A) m= (5-1)/(2-4)= -2
B) m= (5-0)/(10-0) = 1/2
C) m= undefined
D) m= 0
The secant tangent theorem states that the distance from (y to the tangent point x) squared = the external segment * length of the secant.
Put in plane English
YX^2 = YV * YZ
YV = 9
YZ = 9 + 19 = 28
YX^2 = 28 * 9
yX^2 = 252
YX = sqrt(252)
YX = 15.87