Answer:
20 +/- $6.74
= ( $13.26, $26.74)
The 90% confidence interval for the difference in average amounts spent on textbooks (math majors - English majors) is ( $13.26, $26.74)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x1-x2 +/- margin of error
x1-x2 +/- z(√(r1^2/n1 + r2^2/n2)
Given that;
Mean x1 = $200
x2 = $180
Standard deviation r1 = $22.50
r2 = $18.30
Number of samples n1 = 60
n2 = 40
Confidence interval = 90%
z(at 90% confidence) = 1.645
Substituting the values we have;
$200-$180 +/-1.645(√(22.5^2/60 +18.3^2/40)
$20 +/- 6.744449847374
$20 +/- $6.74
= ( $13.26, $26.74)
The 90% confidence interval for the difference in average amounts spent on textbooks (math majors - English majors) is ( $13.26, $26.74)
The answer for this will be a
Answer:
45 yards and 176 yards
Step-by-step explanation:
Perimeter of a rectangular playing field = 2(Length + width)
P = 2(L+W)..................... Equation 1
From the question,
Let the width of the rectangular playing field = x yards,
The the Length = 4x-4 yards.
Given: P = 442 yards.
Substitute these values into equation 1
442 = 2(4x-4+x)
442/2 = 5x-4
221 = 5x-4
5x = 221+4
5x = 225
x = 225/5
x = 45 yards.
Width = 45 yards.
Length = (45×4)-4 yards = 176 yards
Hence the dimensions of the playing field are, 45 yards and 176 yards
Answer:
65038.55
Step-by-step explanation:
First, Let's turn 12.3% into a decimal which is 0.123
Then Multiply 57,915 by 0.123
57,915 × 0.123= 7123.545 Round; 7,123.55
Then Add [Mark up = Add] 57,915 with 7,123.55
57,915 + 7,123.55= 65038.55
Hence, the Answer is 65038.55
Answer:
democracy
Step-by-step explanation:
i guessed
