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3 years ago

Solve the literal equation for y y a=9y 3yx

Mathematics

2 answers:

Travka [436]3 years ago

4 0

Hello there.

<span>y a=9y 3yx

0</span>

Readme [11.4K]3 years ago

4 0

Answer:

$y=\frac{a}{(9+3x)}$

Step-by-step explanation:

we have

$a=9y+3yx$

Solve for y

That means -----> isolate the variable y

Step 1

Factor the variable y in the right side

$a=y(9+3x)$

Step 2

Divide by $(9+3x)$ both sides

$a/(9+3x)=y(9+3x)/(9+3x)$

Step 3

Simplify

$y=\frac{a}{(9+3x)}$

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Suppose an arrow is shot upward on the moon with a velocity of 44 m/s, then its height in meters after tt seconds is given by h(

andreev551 [17]

Answer:

a. 38.19m/s

b. 38.605m/s

c. 38.937m/s

d. 39.0117m/s

e. 39.01917m/s

Step-by-step explanation:

The average velocity is defined as the relationship between the displacement that a body made and the total time it took to perform it. Mathematically is given by the next formula:

$v_a_v_g = \frac{\Delta x}{\Delta t} =\frac{x_f-x_i}{t_f-t_i}$

Where:

$x_f=Final\hspace{3}distance\hspace{3}traveled\\x_i=Initial\hspace{3}distance\hspace{3}traveled\\t_f=Final\hspace{3}time\hspace{3}interval\\t_i=Initial\hspace{3}time\hspace{3}interval$

a. Let's find h(3) and h(4) using the data provided by the problem:

$h(3)=44(3)-0.83(3^2)=124.53=x_i\\h(4)=44(4)-0.83(4^2)=162.72=x_f$

The average velocity over the interval [3, 4] is :

$v_a_v_g=\frac{162.72-124.53}{4-3} =38.19m/s$

b. Let's find h(3.5) using the data provided by the problem:

$h(3.5)=44(3.5)-0.83(3.5^2)=143.8325=x_f$

The average velocity over the interval [3, 3.5] is :

$v_a_v_g=\frac{143.8325-124.53}{3.5-3} =38.605m/s$

c. Let's find h(3.1) using the data provided by the problem:

$h(3.1)=44(3.1)-0.83(3.1^2)=128.4237=x_f$

The average velocity over the interval [3, 3.1] is :

$v_a_v_g=\frac{128.4237-124.53}{3.1-3} =38.937m/s$

d. Let's find h(3.01) using the data provided by the problem:

$h(3.1)=44(3.01)-0.83(3.01^2)=124.920117=x_f$

The average velocity over the interval [3, 3.01] is :

$v_a_v_g=\frac{124.920117-124.53}{3.01-3} =39.0117m/s$

e. Let's find h(3.001) using the data provided by the problem:

$h(3.001)=44(3.001)-0.83(3.001^2)=124.5690192=x_f$

$v_a_v_g=\frac{124.5690192-124.53}{3.001-3} =39.01917m/s$

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lapo4ka [179]

Answer:

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3 years ago

The balcony of an apartment is 4 feet by 7 feet. On a scale drawing of the apartment, the balcony is 0.8 inch by 1.4 inches, and

ratelena [41]

First you must find the scale.
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Divide 7 by 1.4.
That also gives you 5.
This means the scale drawing is 5 times smaller than the real dimensions.

On the scale drawing, the kitchen is 2.4 by 2.8 inches.
All you have to do is multiply both of these by 5 and change it to feet.
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Marina86 [1]

Answer:

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Step-by-step explanation:

The exponent will be negative as the number is less than 1.

After the decimal point there are 11 digits up to and including the 9.

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The product of the two numbers is 36 the GCF of the two numbers is 9 what is the LCM