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olga2289 [7]
4 years ago
13

The population of a town was 230000. For 12 years, the population grew 4% per year, compounded continuously. When was the popula

tion at the end of the 12 year period according to the exponential growth function?

Mathematics
1 answer:
allochka39001 [22]4 years ago
3 0

Answer:

300098

Step-by-step explanation:

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Solve:3x-8y=-33<br><br> solve:9x+8y=29<br><br> show work please
TiliK225 [7]

Answer:

for the first one: x = -25/3 or -8.333333

for the second one: x = 29-8y/9

Step-by-step explanation:

for the first one:

add 8 to both sides 3x=-33 + 8

simplify -33+8 to -25

divide both sides by 3

which gives you -25/3 or 8.333333

for the second one:

subtract 8y from both sides 9x=29-8y

divide both sides by 9

which gives you x= 29-8y/9

6 0
3 years ago
A book of coupons contains 18 restaurant coupons, 12 hotel coupons, and 9 movie theater coupons. What fraction of the coupons ar
Svet_ta [14]
18= 18/100= 9/50 in simplest form
6 0
3 years ago
the average marks of the first 10 students are 17 and that of the next 15 students is 18. find the mean of 25 students?
Alex787 [66]

Answer:

20

_____

10 = 17

15 = 18

20 = 19

25 = 20

6 0
3 years ago
What is the quotient when the sum of 9 and 3 is divided by the difference of 9 and 3
kobusy [5.1K]
<span>sum of 9 and 3 = 12
</span><span>difference of 9 and 3 = 6 

</span><span>the quotient when the sum of 9 and 3 is divided by the difference of 9 and 3:

12/6 = 2</span>
3 0
4 years ago
Read 2 more answers
Determine whether the integral is convergent or divergent. ∫[infinity] 2 e^−1/x / x^2 dx : O Convergent O divergent If it is con
monitta

Let f(x)=e^{-1/x}. Then f'(x)=\frac1{x^2}e^{-1/x}>0 for all x\ge2, so f is strictly increasing. As x\to\infty, e^{-1/x}\to e^0=1, so f is bounded above by 1. This is to say,

e^{-1/x}

and the integral of \frac1{x^2} converges over the same domain, so this integral must also converge by comparison.

We have, by setting y=-\frac1x,

\displaystyle\int_2^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx=\int_{-1/2}^0e^y\,\mathrm dy=e^0-e^{-1/2}=1-\frac1{\sqrt e}

8 0
3 years ago
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