Answer:
31
Step-by-step explanation:
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Answer:
Step-by-step explanation:
|√2-y|=|y-√2|
√2-y=±(y-√2)
when √2-y=y-√2
y+y=√2+√2
2y=2√2
y=√2
when √2-y=-(y-√2)
√2-y=-y+√2
or 0=0
it gives no value of y.
so only possible value is y=√2
I'll do 3 and 4, and you can do 5 and 6 on your own!
For 3, we know that a perpendicular line's slope is -1/the other one, so the form is y=x/5+b (b being any number). Plugging -5 and -3 in, we get -3=-1+b. Adding 1 to both sides, we get -2=b and our equation being y=x/5-2 (since our standard form is y=mx+b with y and x remaining variables)
For 4, parallel means the same slope, so we have y=-2x/5+b. Plugging (2,4) in, we get 4=-4/5+b. Adding 4/5 to both sides, we get 4+4/5=b and our equation being y=-2x/5+4+4/5
