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Andreyy89
4 years ago
12

X^2-5x-8=0 find the roots (zeros)

Mathematics
1 answer:
melomori [17]4 years ago
5 0

Answer:

             x_1=\dfrac{5-\sqrt{57}}{2}\ ,\quad x_2=\dfrac{5+\sqrt{57}}{2}

Step-by-step explanation:

x^2-5x-8=0\\\\a=1\,,\ b=-5\,,\ c=-8\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-(-5)\pm\sqrt{(-5)^2-4\cdot1\cdot(-8)}}{2\cdot1}=\dfrac{5\pm\sqrt{25+32}}{2}=\dfrac{5\pm\sqrt{57}}{2}

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If we divide 56 by 4 we get 14.  Why by4?  So that one number is 3 times the other So he had 14 balls that went into the green bags and 42 (56-14) that went into the red bags.  We could just answer the question and say 14 but I think they want to know how many in each green bag.
14 and 42 don't work because they are not the same number of balls.  What number is a common factor?  7 is,
We could have 2 green bags and split the 14 balls into 2 groups of 7 and with the remaining 42 - put them into 6 red bags of 7 each.
And so the answer to your question is:
7 ball in each bag  = 2 bags are green, and 6 bags are red
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6 0
3 years ago
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4 0
2 years ago
If f(x)= x-3 over x and g(x)= 5x-4 what is the domain of (f•g)(x)
marusya05 [52]

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3 years ago
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3 years ago
(08.06)
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