74 is a composite number. 74=1*74 or 2*37. Factors of 74: 1,2,37,74. Prime factorization: 74=2*37.
The answer is in the box. The 2 units are 6 and the hight of it.
2|7 − 7x| = 2x + 4
|7 - 7x| = x + 2
7 - 7x = x + 2 or 7 - 7x = -(x + 2)
-8x = -5 or 7 - 7x = -x - 2
x = 5/8 or -6x = -9
x = 5/8 or x = 9/6
x = 5/8 or x = 3/2
To check for extraneous solutions, we check both solutions in the original equation.
<em>Check solution 5/8:</em>
2|7 - 7x| = 2x + 4
|7 - 7x| = x + 2
|7 - 7 * 5/8| = 5/8 + 2
|56/8 - 35/8| = 5/8 + 16/8
21/8 = 21/8
<u>Solution x = 5/8 works.</u>
<em>Check solution 3/2:</em>
2|7 - 7x| = 2x + 4
|7 - 7x| = x + 2
|7 - 7 * 3/2| = 3/2 + 2
|14/2 - 21/2| = 3/2 + 4/2
|-7/2| = 7/2
7/2 = 7/2
<u>Solution 3/2 also works.</u>
Answer: x = 5/8 or x = 3/2
Answer: c
Step-by-step explanation: layout B needs about 2.3m more fencing.
The question is missing the detail, it is to find the dimensions of the largest field that can be fenced in.
The formula for area is : A = xy
The perimeter of the fencing is equal to the sum of two widths and the length: 2x + y = 3000
Now, solve the second equation: y = 3000 – 2x
When you plug this expression to the formula for the area, we will get:
A = x (3000-2x) = 3000x – 2x^2
Next take the derivative and equal it to 0: dA/dx = 3000 – 4x = 0
Now solve for x, it will give us 750.
Find the second derivative.
d^2 A / dx^2 = -4
since we have a negative result, x = 75- is a maximum. Then plug this in to x:
3000 – 2 (750) = 1500. The largest field will measure 750 ft by 1500 ft.