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amm1812
4 years ago
13

Which of the following relations describes a function?

Mathematics
1 answer:
Nikolay [14]4 years ago
7 0
The answer is “B” because a function happens when one input has exactly one output, or if each x-value has one y-value
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Work out the area of triangle ABC.
SVETLANKA909090 [29]

Answer:

4 cm²

Step-by-step explanation:

Area = ½.bh

b = base (cm²)

h = perpendicular height, i.e. BD (cm²)

h^{2}  = (2 \sqrt{5} )^{2}  - (3 \sqrt{2} )^{2} \\  {h}^{2}  = 20 - 18 \\  {h}^{2}  = 2 \\ h \:  =  \sqrt{2}

b \:  =  3\sqrt{2}  +  \sqrt{2}  \\ b \:  = 4 \sqrt{2}

Area \:  =  \frac{1}{2} .(4 \sqrt{2} )( \sqrt{2} ) \\ Area \:  =4

6 0
3 years ago
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Which graph does NOT represent a function? <br> Please I need an answer
kotykmax [81]
The first graph (the vertical line) does not represent a function.
7 0
3 years ago
Find f(4) based on the table below.
Softa [21]
The answer for your question is B:4

5 0
3 years ago
Find the equation of the line that passes through the point (7,5) and is perpendicular to the line 2x - 3y=6
balu736 [363]
(7,5);\ \ \ \  2x - 3y=6 \ \ / subtract \ 2x \ from \ each \ side \\ \\-3y = -2x + 6\ \ /  divide \    each \term \ by \ (-3) \\ \\ y =  \frac{2} {3}x -2\\ \\ The \ slope \ is :m _{1} =  \frac{ 2}{3} \\ \\ If \ m_{1} \ and \ m _{2} \ are \ the \ gradients \ of \ two \ perpendicular \\ \\ lines \ we \ have \\\\\ m _{1}*m _{2} = -1

\frac{2}{3}\cdot m_{2}=-1\ \ / \cdot (\frac{3}{2})\\\\m_{2}=-\frac{3}{2}\\\\Now \ your \ equation \ of \ line \ passing \ through \ (7,5) would \ be: \\ \\ y=m_{2}x+b \\ \\5=-\frac{3}{2}\cdot 7  + b \\ \\ 5= -\frac{21}{2}+b\\ \\b=5+\frac{21}{2} \\ \\b= \frac{10}{2}+\frac{21}{2}\\ \\b= \frac{31}{2}\\\\b=15.5 \\ \\ y = -\frac{3}{2}x +15.5
8 0
3 years ago
The price of a particular stock is represented by the linear equation y = negative 0.91 x + 103.47, where x represents the numbe
Yuri [45]

Answer:

$92.55

Step-by-step explanation:

Substitute the value of x, which is in weeks, to 12.

so y = 0.91(12) + 103.47

y = 92.55

5 0
3 years ago
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