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olya-2409 [2.1K]
3 years ago
6

For what value of n is -4 + (-3) + 5 + 4 + (-3) + n/-7 = 0 true?

Mathematics
1 answer:
solniwko [45]3 years ago
4 0

Answer:

n = -7

Check:

-4 - 3 + 5 + 4 - 3 + (-7 ÷ -7) = 0

-1 - 7 ÷ -7 = 0

-1 + 1 = 0

0 = 0

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What is 3 divided by what equals 36
Vedmedyk [2.9K]
3/x=36

Multiply both sides by x
3=36x

Then divide both sides by 36
3/36=x
1/12=x

Final answer: 1/12
6 0
3 years ago
Plz help can anybody solve this only one question​
stiks02 [169]

Step-by-step explanation:

Angle:2x+30+3x=180

Angle:2x+b+2b=180( Being in straight line)

Angle:30+3x+a=180

5 0
3 years ago
Kendrick received 24 fewer e-mails than he did on Thursday. If he received a total of 126 e-mails on those two days, how many di
telo118 [61]
E+(e-24)=126

2e-24=126

2e=150

e=75

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3 0
3 years ago
There are about 1.4×109 cubic kilometers of water on Earth. About 2.5% of the water is fresh water. How much fresh water is on E
Sveta_85 [38]

Answer:

Amount of fresh water = 3.5 * 10^7 cubic kilometers

Step-by-step explanation:

Given the following

Total water on earth = 1.4×10^9 cubic kilometers

If 2.5% of it is fresh water

Amount of fresh water = 2.5% of 1.4×10^9

Amount of fresh water = 0.025 * 1.4×10^9

Amount of fresh water = 0.035 * 10^9

Amount of fresh water = 3.5 * 10^7 cubic kilometers

8 0
3 years ago
You are giving 24 linear feet of fencing all 3 feet tall you wish to make the largest rectangular enclosure possible to maximize
earnstyle [38]

Answer:

The largest area enclosed is  A = xy = 6 feet \times 6 feet = 36 feet^{2}

Step-by-step explanation:

i) The perimeter of the area is 2\times(x + y) =24  ∴ x + y = 12    ∴ y = 12 - x

ii) The area of rectangle enclosed A  = xy    ⇒ A  = x ( 12 - x) = 12x - x^{2}

iii) differentiating both sides of the equation in ii) we get

\dfrac{dA}{dx} = 12 - 2x = 0    ⇒  x = 6 feet

iv) Differentiating both sides of equation in iii) we get    \frac{d^{2}A}{dx^{2} } =  -2

   Therefore the area enclosed is maximum as the double derivative is negative

v) therefore for largest area enclosed   x  = 6 feet and  y = 12 - 6 = 6 feet

vi) therefore the largest area enclosed is

 A = xy = 6 feet \times 6 feet = 36 feet^{2}

7 0
3 years ago
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