Answer:
anonymity
Explanation:
<h2><u>Fill in the blanks </u></h2>
Proponents of Internet freedom see its <u>anonymity </u>as providing protection for unpopular expression; proponents of greater Internet control see it as the Internet's greatest danger.
Answer:
Sniffing.
Explanation:
Data theft can be defined as a cyber attack which typically involves an unauthorized access to a user's data with the sole intention to use for fraudulent purposes or illegal operations. There are several methods used by cyber criminals or hackers to obtain user data and these includes DDOS attack, SQL injection, man in the middle, phishing, sniffing, etc.
Sniffing can be defined as a form of cyber attack in which a malicious user gains access to a private network with the intent of finding out what information is stored on the network.
A packet sniffer also known as a packet analyzer, is a computer software or hardware tool that can be used to intercept, log and analyze network traffic and data that passes through a digital network.
Basically, an unauthorized packet sniffer is used to steal user informations.
This ultimately implies that, sniffing typically involves monitoring and capturing internet traffic (data packets) that are transmitted through a private network in real-time by using a sniffing tool, which may either be a hardware or software.
In this scenario, a malicious user in an airport terminal seating area was able to connect wirelessly to a traveling employee's smartphone and downloaded her contact list. Thus, the type of attack that has taken place is referred to as sniffing.
Answer:
The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.
![rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)](https://tex.z-dn.net/?f=rank%28A%29%3Drank%5Cleft%20%28%20%5Cleft%20%5B%20A%7CB%20%5Cright%20%5D%20%5Cright%20%29%5C%3Aand%5C%3An%3Drank%28A%29)
Then satisfying this theorem the system is consistent and has one single solution.
Explanation:
1) To answer that, you should have to know The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.
![rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)](https://tex.z-dn.net/?f=rank%28A%29%3Drank%5Cleft%20%28%20%5Cleft%20%5B%20A%7CB%20%5Cright%20%5D%20%5Cright%20%29%5C%3Aand%5C%3An%3Drank%28A%29)

Then the system is consistent and has a unique solution.
<em>E.g.</em>

2) Writing it as Linear system


3) The Rank (A) is 3 found through Gauss elimination


4) The rank of (A|B) is also equal to 3, found through Gauss elimination:
So this linear system is consistent and has a unique solution.
Geofencing Marketing refers to the use of gps or rfid technology to create virtual boundaries that enable software to trigger a response when a mobile device enters or leaves a particular area.
<h3>What is Geofencing Marketing?</h3>
- Geofencing marketing is an illustration of a real-time location-based trade tactic that utilizes geolocation data to mark users within a specified geographic region and delivers a range based on where they are or in what areas they have previously visited.
- Geofencing marketing concerns setting up virtual borders around a point or area that tracks whenever someone with a portable device crosses them.
To learn more about Geofencing Marketing, refer:
brainly.com/question/9795929
#SPJ4
In your "count spaces method" before the for loop, you want to declare an int variable (let's call it spc)
then, each time you find that charat, spc++.
also, the string must be declared in the main method, not the spaces count method.
The actual code:
public class CountSpaces{
public static void main(String[] args){
String instring = "(your quote here)";
int spaces = calculateSpaces(instring);
System.out.println("The number of spaces is " + spaces);
}
public static int calculateSpaces(String in){
int spc = 0;
for(int i= 0; i<in.length; i++){
if(in.charAt(i)== ' '){
spc++;
}
}
return spc;
}
}
that should be it. If you have any questions, feel free to reach out.