Answer:
see below for a graph
Step-by-step explanation:
The first inequality does not include the "equal to" case, so its boundary is graphed with a dashed line. If we consider only the y term, we have y < ..., so the shading is below the line.
__
The second inequality includes the "equal to" case, so its boundary line is solid. Again, considering only the y-term, we have y ≥ ..., so the shading is above the line.
__
We find that points (-6, 0) and (0, 6) will satisfy both inequalities, as will any point in the doubly-shaded area.
