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Grace [21]
3 years ago
15

O.496 in word form please help me

Mathematics
1 answer:
aniked [119]3 years ago
8 0
Zero and four hundred ninety six
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Sabrina bought a hoodie at the store when they were having a 25% off sale. If the regular
Rina8888 [55]

Answer:

$12.50

Step-by-step explanation:

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3 years ago
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-10(1 - 9x) + 6(x - 10) <br> Pics pls
Galina-37 [17]

Answer:

  • \boxed{\sf{96x-70}}}

Step-by-step explanation:

Use the distributive property.

<h3>What is a distributive property?</h3>

Distributive property is a serving to distribute or allot or disperse.

<u>Distributive property:</u>

A(B+C)=AB+AC

A(B-C)=AB-AC

-10(1-9x)+6(x-10)

<u>Expand.</u>

-10(1-9x)

-10*1=-10

-10*9x=90x

\longrightarrow \sf{=-10+90x+6\left(x-10\right)}}

6(x-10)

6*x=6x

6*10=60

6x-60

<u>Rewrite the problem down.</u>

= -10+90x+6x-60

<u>Combine like terms.</u>

90x+6x-10-60

<u>Add the numbers from left to right.</u>

90x+6x=96x

96x-10-60

<u>Finally, subtract the numbers from left to right.</u>

-10-60=-70

\Longrightarrow \boxed{\sf{96x-70}}

Therefore, the final answer is<u> 96x-70.</u>

I hope this helps, let me know if you have any questions.

To learn more about distributive property:

brainly.com/question/2807928

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3 0
2 years ago
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Given the function f(x) = 2x-5 and g(x), which function has a greater slope?​
adell [148]

Answer:

g(x) has a greater slope

Step-by-step explanation:

step 1

Find the slope of f(x)

we have

f(x)=2x-5

This is a linear function in slope intercept form

f(x)=mx+b

where

m is the slope

b is the y-intercept

so

m=2

step 2

Find the slope of g(x)

take two points from the table

(2,0) and (4,5)

m=(5-0)/(4-2)\\m=5/2=2.5

step 3

Compare the slopes

2.5 > 2

so

The slope of g(x) is greater than the slope of f(x)

3 0
4 years ago
An article in Technometrics (Vol. 19, 1977, p. 425) presents the following data on the motor fuel octane ratings of several blen
Slav-nsk [51]

Answer:

Median = 90.4

Q_1 = 88.6

Q_3 = 92.2

Step-by-step explanation:

Given

The above data

Required

- A stem and leaf display

- The median

- The quartiles

First, determine the range of the data

Smallest = 83.4

Highest = 100.3

Next, group each dataset base on common whole numbers.

So, we have:

83.4

84.3\ 84.3

85.3

86.7\ 86.7\ 86.7

87.4\ 87.5\ 87.6\ 87.7\ 87.8\ 87.9

88.2\ 88.3\ 88.3\ 88.3\ 88.4\ 88.5\ 88.5\ 88.6\ 88.6\ 88.7\ 88.9

89.0\ 89.2\ 89.3\ 89.3\ 89.6\ 89.7\ 89.8\ 89.8\ 89.9\ 89.9

90.0\ 90.1\ 90.1\ 90.1\ 90.3\ 90.4\ 90.4\ 90.4\ 90.5\ 90.6\ 90.7\ 90.8\ 90.9

91.0\ 91.0\ 91.0\ 91.1\ 91.1\ 91.1\ 91.2\ 91.2\ 91.2\ \ 91.5\  91.6\ 91.6\ 91.8\ 91.8

92.2\ 92.2\ 92.2\ 92.3\ 92.6\ 92.7\ 92.7\ 92.7

93.0\ 93.2\ 93.3\ 93.3\ 93.4\ 93.7

94.2\ 94.2\ 94.4\ 94.7

96.1\ 96.5

98.8

100.3

Next, we construct the stem and leaf plot.

The whole numbers will be the stem while the decimal parts will be the leaf.

So, we have:

\begin{array}{ccc}{Stem} & {} & {Leaf} & {83} & {|} & {.4} & {84} & {|} & {.3\ .3} & {85} & {|} & {.3} & {86} & {|} & {.7\ .7\ .7} & {87} &{|} & {.4\ .5\ .6\ .7\ .8\ .9} & {88} & {|} & {.2\ .3\ .3\ .3\ .4\ .5\ .5\ .6\ .6\ .7\ .9} &{89} & {|} & {.0\ .2\ .3\ .3\ .6\ .7\ .8\ .8\ .9\ .9} & {90} & {|} &{.0\ .1\ .1\ .1\ .3\ .4\ .4\ .4\ .5\ .6\ .7\ .8\ .9} & {91} &{|}&{.0\ .0\ .0\ .1\ .1\ .1\ .2\ .2\ .2\ .5\ .6\ .6\ .8\ .8} &{92} &{|} &{.2\ .2\ .2\ .3\ .6\ .7\ .7\ .7} \ \end{array}

  \begin{array}{ccc} {93} & {|} & {.0\ .2\ .3\ .3\ .4\ .7} & {94} &{|} & {.2\ .2\ .4\ .7} &{96} & {|} & {.1\ .5} & {98} & {|} & {.8} & {100} &{|} &{.3} \ \end{array}

From the above plot,

n = 83

The median is calculated as:

Median = \frac{n+1}{2}th

Median = \frac{83+1}{2}th

Median = \frac{84}{2}th

Median = 42nd

i.e. the median is at the 42nd position.

From the above stem and leaf plot.

The 42nd position is at stem 90 and the leaf  .4

So the median is:

Median = 90.4

The lower quartile (Q) is calculated as:

Q_1 = \frac{n+1}{4}th

Q_1 = \frac{83+1}{4}th

Q_1 = \frac{84}{4}th

Q_1 = 21st

i.e. the lower quartile is at the 21st position.

From the above stem and leaf plot.

The 42nd position is at stem 88 and the leaf .6

So the lower quartile is:

Q_1 = 88.6

The upper quartile (Q3) is calculated as:

Q_3 = 3 * \frac{n+1}{4}th

Q_3 = 3 * \frac{83+1}{4}th

Q_3 = 3 * \frac{84}{4}th

Q_3 = 3 * 21th

Q_3 = 63rd

i.e. the upper quartile is at the 63rd position.

From the above stem and leaf plot.

The 63rd position is at stem 92 and the leaf .2

So the upper quartile is:

Q_3 = 92.2

8 0
3 years ago
-2 x + 4 &gt; -4x + 8. helppp
Lilit [14]

Answer:

1/2 but unsure

Step-by-step explanation:

I solved for X and I got 1/2 I want to verify what you are solving for so I could further help you

7 0
3 years ago
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