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baherus [9]
3 years ago
13

Solve for x. A) 10.5 B) 10 C) 6√3 D) 20

Mathematics
1 answer:
faltersainse [42]3 years ago
8 0
There are three right triangles in this figure.  Set up Pythagorean theorem for each of them.
Let y be the altitude of the largest triangle.
Let z be the left side.
We have for large triangle:
x² + z² = (9+3)²
For left sub-triangle:
y² + 3² = z²
For right sub-triangle:
y² + 81 = x²

So the three equations are
x² + z² = 144
y² + 9 = z²
y² + 81 = x²

Solve last equation for y², plug into second equation, solve that for z² in terms of x², and lastly plug z² into the first equation to find
x² + x² - 72 = 144
2x² = 216
x² = 108
x = √108 = √(36·3) = 6√3

The answer is C) 6√3
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Answer:

The maximum distance is 17.5 miles

No she can't make to the airport.

Step-by-step explanation:

Given the cab charges $0.8 per mile and $2 for tolls.

let the miles travelled by melissa be x.

The total charge is $(0.8*x+2)

Now given that she can spend a maximum of $16

so the inequality is

0.8*x+2\leq 16

0.8*x\leq 14

x\leq \frac{14}{0.8}

x\leq 17.5

Therefore the maximum distance she can travel is 17.5 miles

Since the distance to airport is 25 miles which is greater than 17.5 miles she cannot afford the cab.

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4 years ago
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<h3>Answer:  40%</h3>

Work Shown:

48/120 = 0.40 = 40%

6 0
2 years ago
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Uhhhhhmmmmmmmmmmmm wuts dis
vichka [17]

Answer:

Hey!

Step-by-step explanation:

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3 years ago
(3 x 10e-4) ( 3 x 10e7)
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A particular circle in the standard (x,y) coordinate
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For any circle with Cartesian equation
(x-a)^2 + (y-b)^2 = r^2,
we have that the centre of the circle is (a,b), and the radius of the circle is r.

So in the case that 
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we essentially have that
a = 5, b = 0, r^2 = 38.

So the centre of the circle is (5,0), and the radius is \sqrt{38}.
7 0
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