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3 years ago

I need to know the answers

Mathematics

2 answers:

arsen [322]3 years ago

8 0

For answers 17-30 all you need to do is determine the quadrant the points are in. The points are in order of (x,y) , “x” is the horizontal line and “y” is the vertical. (I’m sure you know that) if you don’t know , to the left of (0,0) (where x and y intersect) , all x values are negative, and to the right they are all positive. For “y” the values on top of (0,0) are positive and below (0,0) are negative. So for example, for number 17. (-5,2) the point will be in the top left quadrant because that’s where x is negative (-5) and y is positive (2). Not sure if that’s what you are looking for, you may know all this already but from your question that’s what I assumed you needed help with. Hope this helps! If not sorry.

kkurt [141]3 years ago

7 0

Answer:

for which problems if it is all the ones you haven't done yet then say that.

Step-by-step explanation:

i dont know how to gragh pionts on this thing plz tell me how

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The measure of an angle is 12°. What is the measure of its supplement?<br> *No answer just number*

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Answer:

168°

Step-by-step explanation:

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3 years ago

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Rylee is learning about prime numbers in math class. Her friend ask her to name all prime number between 10 and 20. What numbers

Juli2301 [7.4K]

Answer:

11, 13, 17, 19

Step-by-step explanation:

If you look at the prime numbers chart between 10 and 20, there are:

11, 13, 17, 19

Those are all of the prime numbers that are between 10 and 20.

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3 years ago

Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1

elena-s [515]

Answer:

a) $P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

b) $P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

c) $0.75 =\frac{0.83}{1+e^{-0.2n}}$

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

d) If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

$P(n) = \frac{0.83}{1+e^{-0.2t}}$

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

$P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

So the number of correct reponses after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

$P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

$0.75 =\frac{0.83}{1+e^{-0.2n}}$

And we can rewrite this expression like this:

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

Now we can apply natural log on both sides and we got:

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

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3 years ago

Six of 16 students in Mr. McConney's class are serving detentions, the rest are here for tutoring. What percent of students are

Ivan

Answer:

62.5%

Step-by-step explanation:

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3 years ago

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The perimeter of a rectangular field is 320320 yd. the length is 2020 yd longer than the width. find the dimensions.

hichkok12 [17]

The sum of length and width is half the perimeter, 160 yd. The length is the average of the sum and difference of dimensions:
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Then the width is 160 -90 = 70

The rectangular field is 70 yd by 90 yd.

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3 years ago