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MAVERICK [17]
3 years ago
6

Solve for e. 9e^2f = 49

Mathematics
1 answer:
ELEN [110]3 years ago
3 0
9e^{2f}=49
e^{2f}=\dfrac{49}9
(e^{2f})^{1/(2f)}=\left(\dfrac{49}9\right)^{1/(2f)}
e=\left(\dfrac{49}9\right)^{1/(2f)}

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