Question

Solve for e. 9e^2f = 49

Answer 1

$9e^{2f}=49$
$e^{2f}=\dfrac{49}9$
$(e^{2f})^{1/(2f)}=\left(\dfrac{49}9\right)^{1/(2f)}$
$e=\left(\dfrac{49}9\right)^{1/(2f)}$