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Serjik [45]
3 years ago
14

HELP PLEASEWhat is the value of the exponential expression below?

Mathematics
2 answers:
vladimir2022 [97]3 years ago
6 0
Hi, I got C because you just put 1/2 in for an exponent.. so, 16 of an exponent of 1/2.. it would be letter C. 4
babunello [35]3 years ago
4 0
Square root of 16. Equals 4
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John went to a deli on his lunch hour. He bought 1.3 lb. of roast beef and 0.6 lb. of cheese. Both were on sale for $3.99 per po
Goryan [66]

Answer:

5.19 for the roast beef & 2.39 for the cheese. 7.58$

10.00$-7.58$=3.42$

5 0
2 years ago
Help!!!! giving brainiest!!!
Margarita [4]
Hi there!

In order to find x, we'll need to create an expression. We know that angle x would be 180 - angle ABC - y. Since we know that angle ABC is equal to 30, we can substitute that in. This gives us 180 - 30 - y. Lastly, we can simplify to get our expression. The expression is 150 - y. The answer is the first option.

Hope this helps!! :)
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7 0
3 years ago
Solve 4x−9y=13 for y.
Irina18 [472]

Answer:

y =  -  \frac{13}{9}  +  \frac{4}{9} x

Step-by-step explanation:

4x - 9y = 13

4x - 9y - 4x = 13 - 4x

- 9y = 13 - 4x

y = 9y \div (9) = (13 - 4x) \div ( - 9)

y = (13 - 4x) \div( - 9)

y = 13 \div ( - 9) - 4x \div ( - 9)

y =  - 13 \div 9 - 4x \div ( - 9)

y =  -  \frac{13}{9}  - 4x \div ( - 9)

y =  -  \frac{13}{9}  + 4x \div 9

\boxed{\green{y =  -  \frac{13}{9}  +  \frac{4}{9} x, x E R}}

8 0
3 years ago
If the initial velocity stays the same, but the height the projectile is launched from changes , how would the amount of time ch
pickupchik [31]

Answer:

Part A

The height to which the projectile reaches is given by the following formula;

\Delta y = y-y_0 = v_{0y} \times t-\dfrac{1}{2} \times g \times t^2

Where;

v_{0y} = The initial velocity of the projectile = Stays the same

y = The height the projectile reaches

y₀ = The height from which the projectile is launched

g = The acceleration due to gravity

t = The time taken

Given that the projectile has the same initial velocity, the variation of Δy with time, 't', will be the same when the project is launched from a different height, and the time change that it takes for the projectile to reach the maximum height will be the same for the previous launch height

Part B

From the change in eight of the projectile, Δy = y - y₀, the maximum height reached, 'y', is therefore given as follows;

y = Δy + y₀

The maximum height will increase by 'y₀', where 'y₀' is the difference between new height and the previous height, y_i

That is, if y₀ > y_i, the maximum height reached increases and if y₀ < y_i, y₀ will be added as y = Δy - y₀ and the maximum height reached decreases

Step-by-step explanation:

6 0
2 years ago
Fingernails grow 1.5 inches per year. How long would it take to grow them 37 inches
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